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DIA [1.3K]
3 years ago
14

A square has a length of 2(m+3). What is the perimeter of the square?

Mathematics
2 answers:
katen-ka-za [31]3 years ago
6 0

Answer:

8(m+3)

or 8m+24

Step-by-step explanation:

If one side x has a length of 2(m+3), then using the formula for the perimeter of a square P=4x

You get:

8(m+3)

or 8m+24

ale4655 [162]3 years ago
6 0

Answer:

8m + 24

Step-by-step explanation:

First, distribute the 2 so it will be easier to find the perimeter:

2(m + 3)

= 2m + 6

Since a square has 4 sides, we need to add this expression together 4 times:

(2m + 6) + (2m + 6) + (2m + 6) + (2m + 6)

Add like terms:

2m + 2m + 2m + 2m

= 8m

6 + 6 + 6 + 6

= 24

Add those together:

8m + 24 will be the perimeter

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Perform the indicated row operations, then write the new matrix.
Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]

Operations:

2R_1 + R_2 ->R_2

-3R_1 +R_3 ->R_3

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]

Step-by-step explanation:

The first operation:

2R_1 + R_2 ->R_2

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]

Multiply by 2

2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]

Add to row 2 elements are: \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]

\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]

\left[\begin{array}{ccc}0&5&7|1\end{array}\right]

The second operation:

-3R_1 +R_3 ->R_3

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]

Multiply by -3

-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]

Add to row 2 elements are: \left[\begin{array}{ccc}3&2&4|1\end{array}\right]

\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]

\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]

Hence, the new matrix is:

\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]

3 0
3 years ago
Read 2 more answers
20x+32y=0 <br> -50x-80y=0
german

Answer:

dont know what you need

Step-by-step explanation:

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4 0
3 years ago
If rain is falling at 0.5 inches per hour and 1.5 inches have already accumulated, how many hours must have passed if there are
zavuch27 [327]

Given :

Rain is falling at 0.5 inches per hour and 1.5 inches have already accumulated.

To Find :

How many hours must have passed if there are 5 inches of rain .

Solution :

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We know , general equation of line :

y = mx +c

Here , m = 0.5 and c = 1 .

So , equation of rain accumulated is :

y=0.5x+1

Now , putting value of x = 5 hours .

We get :

y=0.5\times 5+1\\\\y=2.5+1=3.5\ inches

Hence , this is the required solution .

7 0
3 years ago
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gulaghasi [49]
The answer is 5/6 of a pound.
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Elan Coil [88]
The answer is B because if you check it again it will be the same <3
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