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AysviL [449]
2 years ago
15

Determined to finish his mocha frappe before daniela,jeremy now drinks his 12-ounce mocha frappe at a rate of 1/3 an ounce per s

econd. Daniela starts with her usual 20-ounce mocha frappe and drinks at the same rate as before, 2/3 an ounce per second.
Mathematics
1 answer:
notka56 [123]2 years ago
6 0

Answer:

Daniela finished first.

It will take 36 seconds for Jeremy to finish the drink and Daniela 30, so daniela will finish first.

12 times 1/3 = 36

20 times 1/3= 60, divided by 2, because its 2/3 not 1 third, equals 30

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Geometry <br> I’ll mark brainiest crown thing only for the correct answer tho
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Answer: i think it is ASA

Step-by-step explanation:

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2 years ago
Colleen McHugh wishes to deposit checks for $13.75, $92.08, and $8.21 into her account. She would like to receive $15.00 in cash
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her total deposit is 98.94

4 0
2 years ago
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Since at t=0, n(t)=n0, and at t=∞, n(t)=0, there must be some time between zero and infinity at which exactly half of the origin
Airida [17]
Answer: t-half = ln(2) / λ ≈ 0.693 / λ

Explanation:

The question is incomplete, so I did some research and found the complete question in internet.

The complete question is:

Suppose a radioactive sample initially contains N0unstable nuclei. These nuclei will decay into stable nuclei, and as they do, the number of unstable nuclei that remain, N(t), will decrease with time. Although there is no way for us to predict exactly when any one nucleus will decay, we can write down an expression for the total number of unstable nuclei that remain after a time t:

N(t)=No e−λt,

where λ is known as the decay constant. Note that at t=0, N(t)=No, the original number of unstable nuclei. N(t) decreases exponentially with time, and as t approaches infinity, the number of unstable nuclei that remain approaches zero.

Part (A) Since at t=0, N(t)=No, and at t=∞, N(t)=0, there must be some time between zero and infinity at which exactly half of the original number of nuclei remain. Find an expression for this time, t half.

Express your answer in terms of N0 and/or λ.

Answer:

1) Equation given:

N(t)=N _{0} e^{-  \alpha  t} ← I used α instead of λ just for editing facility..

Where No is the initial number of nuclei.

2) Half of the initial number of nuclei: N (t-half) =  No / 2

So, replace in the given equation:

N_{t-half} =  N_{0} /2 =  N_{0}  e^{- \alpha t}

3) Solving for α (remember α is λ)

\frac{1}{2} =  e^{- \alpha t} &#10;&#10;2 =   e^{ \alpha t} &#10;&#10; \alpha t = ln(2)

αt ≈ 0.693

⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ




4 0
2 years ago
What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?
natulia [17]

Answer:

<em>The endpoint coordinates for the mid-segment are:  (-2,-1) and (1,0)</em>

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of \triangle BCD are:   B(-3,1), C(3,3) and D(-1,-3)

Now, the endpoints of the mid-segment of \triangle BCD which is parallel to BC will be the mid-points of sides BD and CD.

<u>Formula for the coordinate of mid-point</u> :   (\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}), where (x_{1}, y_{1}) and (x_{2}, y_{2}) are two endpoints.

So, the mid-point of BD will be:  (\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)

and the mid-point of CD will be:  (\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)

Thus, the endpoint coordinates for the mid-segment of \triangle BCD that is parallel to BC are  (-2,-1) and (1,0)

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IgorC [24]
87 is grater because 13.988 has a decimal point


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