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Black_prince [1.1K]
3 years ago
5

Y=-x squared - 6x -5 what is the vertex and x-intercepts

Mathematics
1 answer:
Alenkasestr [34]3 years ago
6 0
y=-x ^2  - 6x -5 \\ \\  standard \  form \\ \\y=ax+bx+c \\ \\V(p,q)\\ \\ p=\frac{-b}{2a}=\frac{-(-6)}{-2}=3\\ \\\Delta = b^{2}-4ac =14^{2}-4*1*(-51)=196+204=400 \\ \\q=\frac{-\Delta }{4a} =\frac{-400}{4}=100\\ \\V( 3,100)\\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-14- \sqrt{400}}{2}=\frac{-14-20}{2}= \frac{-34}{2}=-17\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{-14+ \sqrt{400}}{2}=\frac{-14+20}{2}= \frac{6}{2}=3
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chubhunter [2.5K]

Answer:

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Answer:

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Step-by-step explanation:

The law of sines can help figure this.

The remaining angle in the triangle is ...

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This is the angle opposite the leg from the surveyor to the second marker. Referencing the attachment, we have ...

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IceJOKER [234]
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