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damaskus [11]
3 years ago
8

Solve 2w2–64 = 0, where w is a real number.

Mathematics
2 answers:
avanturin [10]3 years ago
6 0

Answer:

w = 4√2

Step-by-step explanation:

2w^2 - 64 = 0

=> 2w^2 = 64

=> w^2 = 32

=> w = √ 32

=> w = √ [(2 x 2) x (2 x 2) x 2]

=> w = 2 x 2 x √ 2

=> w = 4√2

sashaice [31]3 years ago
4 0

Answer:

W=16

Step-by-step explanation:

Because 2*16*2= 64 so it would be 64-64 which is 0

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