Answer:
The Upper Bound of the 99% confidence interval about the mean number of orcs per raiding party is of 106.83 orcs per party.
Step-by-step explanation:
We have the standard deviation of the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 13 - 1 = 12
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 12 degrees of freedom(y-axis) and a confidence level of
. So we have T = 3.0545
The margin of error is:
M = T*s = 3.0545*7.8 = 23.83
In which s is the standard deviation of the sample.
The upper end of the interval is the sample mean added to M. So it is 83 + 23.83 = 106.83 orcs per party.
The Upper Bound of the 99% confidence interval about the mean number of orcs per raiding party is of 106.83 orcs per party.
The scale factor of dilation is 1/2 or

because the number of rectangle one is multiplied by 1/2 to make rectangle 2
good luck
Option A
<u>Answer:
</u>
The value of x in the equation 2(x - 3) + 5x = 5(2x + 6) is -12
<u>Solution:
</u>
From question given that
2(x - 3) + 5x = 5(2x + 6)
Open the brackets,
2x – 6 + 5x = 10x + 30
Rewrite the above equation,
2x + 5x – 6 = 10x + 30
On simplifying the above equation, we get
7x – 6 = 10x + 30
Now adding 6 on both sides,
7x – 6 + 6 =10x + 30 + 6
7x = 10x + 36
On subtracting 10x on both sides,
7x - 10x = 10x + 36 - 10x
-3x = 36
On dividing -3 on both sides,
x = -12
Hence on simplifying 2(x - 3) + 5x = 5(2x + 6) we get value of x is -12. Hence Option (A) is correct.
Answer:
...none of them are correct, but if i had to choose, it'd be A.
Step-by-step explanation: