As it is straight angle so it's answer will be 180.
Answer:
y = 2x + 4
y = 2x + 46x – 3y = -12
y = 2x + 46x – 3y = -12And
y = 2x + 46x – 3y = -12Andy = 2x
y = 2x + 46x – 3y = -12Andy = 2x-8x – 2y = 24
Step-by-step explanation:
hope it helps you
Answer:
The angle is in the first quadrant
Step-by-step explanation:
For angles greate than360°,subtract
360° from the angle until the angle is less than 360°. Hence
405° = 405° - 360°
= 45°
The angle is in the first quadrant. Since the first quadrant can still take as much as 90°
Answer:
Step-by-step explanation:
By applying the concept of calculus;
the moment of inertia of the lamina about one corner 
is:
where :
(a and b are the length and the breath of the rectangle respectively )
![I_{corner} = \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Bbx%5E3%7D%7B3%7D%2B%20%5Cfrac%7Bb%5E3x%7D%7B3%7D%5D%5E%20%7B%5E%20a%7D%20_%7B_0%7D)
![I_{corner} = \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Ba%5E3b%7D%7B3%7D%2B%20%5Cfrac%7Bab%5E3%7D%7B3%7D%5D)
Thus; the moment of inertia of the lamina about one corner is
