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ddd [48]
3 years ago
6

A manufacturing plant earned $80 per man hour of labor when it opened. Each year, the plant earns an additional 5% per man hour.

Write a function that gives the amount A(t) that the plant earns per man hour (t) years after it open.
Mathematics
2 answers:
zalisa [80]3 years ago
6 0

Answer: 80.1.05^t

Step-by-step explanation: got it

Mekhanik [1.2K]3 years ago
3 0

Answer:

The amount that plant earns per man hour after (t) years it open is           $80 (1.05)^{\textrm t} .

Step-by-step explanation:

Given as :

The earning of  manufacturing plant when it opened = $ 80 per man hour

The rate of plant earning per man hour  = 5 %

Let The earning of plant after t years = A( t )

So,

The earning of plant after t years = initial earning × (1+ \dfrac{\textrm rate}{100})^{\textrm Time}

Or, A(t) = $ 80 × (1+ \dfrac{\textrm 5}{100})^{\textrm t}

or, A(t) = $ 80 × (1.05)^{\textrm t}

Hence The amount that plant earns per man hour after (t) years it open is   $80 (1.05)^{\textrm t} . Answer

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<h3>Calculating average speed </h3>

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A local sorority sold hot dogs and bratwursts at the spring fling picnics. The first day they sold 8 dozen hot dogs and 13 dozen
kicyunya [14]

Answer:

1 hot dog costs $0.75

1 bratwurst costs $1.35

Step-by-step explanation:

Let x and y be the price per dozen of hot dogs and bratwursts respectively.

The first day they sold 8 dozen hot dogs and 13 dozen bratwursts for ​$282.60

8x + 13y = 282.60

The second day they sold 10 dozen hot dogs and 15 dozen bratwursts for a total of ​$333.00

10x + 15y = 333

and we have the linear system

<em>8x + 13y = 282.60 </em>

<em>10x + 15y = 333 </em>

which can be written in matrix form as

\bf \left(\begin{array}{cc}8&13\\10&15\end{array}\right)\left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{c}282.60\\333\end{array}\right)

The solution would be given by

\bf \left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{cc}8&13\\10&15\end{array}\right)^{-1}\left(\begin{array}{c}282.60\\333\end{array}\right)

We have  

\bf \left(\begin{array}{cc}8&13\\10&15\end{array}\right)^{-1}=\left(\begin{array}{cc}-3/2&13/10\\1&-4/5\end{array}\right)

hence

\bf \left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{cc}-3/2&13/10\\1&-4/5\end{array}\right)\left(\begin{array}{c}282.60\\333\end{array}\right)=\left(\begin{array}{c}9\\ 16.2\end{array}\right)

Now,

if a dozen hot dogs cost $9, 1 hot dog costs 9/12 = $0.75

if a dozen bratwursts cost $16.2, 1 bratwurst costs 16.2/12 = $1.35

4 0
3 years ago
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