Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
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a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
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b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
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c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo
Answer:
<h2><em><u>2)</u></em><em><u> </u></em><em><u>two</u></em></h2>
Step-by-step explanation:
A line segment forms when it has two end points
Answer:
Kindly check explanation
Step-by-step explanation:
Given that :
Mean (m) = 72
Standard deviation (sd) = 10
Grading cutoff policy:
bottom 5% receive F
next 15% receive D
next 35% receive C
next 30% receive B
A) Give the cutoffs for the grades in this course in terms of standardized scores.
Standardized score for grade cutoff:
Locating the Zscore for the proportions on the z table :
Bottom 5% = 0.05 ; corresponding Zscore = - 1.645
next 15% receive D = (5 +15)% 0.20 ; corresponding Zscore = - 0.84
next 35% receive C = (20+35)% = 0.55 ; corresponding Zscore = 0.13
next 30% receive B = (55 + 30)% = 0.85 ; Corresponding Zscore = 1.04
B) Give the cutoffs in terms of actual total scores.
Recall:
Zscore = (x - m) /sd ; where x = actual score
x = sd*z + m
For F:
10*(-1.645) + 72 = 55.55
For D:
10*(-0.84) + 72 = 63.6
For C:
10*(0.13) + 72 = 73.3
For B:
10*(1.04) + 72 = 82.4
C) Do you think that this method of assigning grades is a good one?
Yes, it is good in terms of expressing scores around the mean such that score below are negative and those above are positive. However, it is a little bit ambiguous.
Answer:
Step-by-step explanation:
The formula for the volume of a cylinder is V = πr²h.
Here, r = 5cm, and h = 15 cm, and so the volume is:
V = πr²h = π(5 cm)²(15 cm), or:
V = π(25 cm²)(15 cm) = 375π cm³, or approximately 1170 cm³
The hyperbola is more or less as in the picture below
notice the traverse axis is horizontal, meaning the positive fraction will be the one with the "x" variable in it, and notice the length of the "a" component
the conjugate axis is 10, notice the length of the "b" component
thus
so, hmmmm plug in those values
