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Sloan [31]
2 years ago
14

Factor each polynomial. Look for a GCF first

Mathematics
1 answer:
weeeeeb [17]2 years ago
7 0

Answer:

20. x\left(x-6\right)\left(x+8\right)

22. 2\left(x+1\right)\left(x+4\right)

24. 5m\left(m-1\right)\left(m+7\right)

Step-by-step explanation:

20. x^3+2x^{2} -48x

The GCF is x, so you group it out of the equation first.

x(x^{2} +2x-48)

Then, you find 2 numbers that will equal to 2 when you add them and will equal to -48 when you multiply them.

?+?=2\\?*?=-48

The two numbers would be -6 and 8. You then differentiate the squares.

x\left(x-6\right)\left(x+8\right)

22. 2x^{2} +10x+8

The GCF is 2, so you must group it out.

2(x^{2} +5x+4)

Find the two numbers that will equal to 5 when you add them and will equal to 4 when you multiply them.

?+?=5\\?*?=4

The two numbers would be 1 and 4. Finally, differentiate the squares.

2\left(x+1\right)\left(x+4\right)

24. 5m^{3} +30m^2-35m

The GCF is 5m, so you must group it out.

5m(m^2+6m-7)

Find the two numbers that will equal to 6 when you add them and will equal to -7 when you multiply them.

?+?=6\\?*?=-7

The two numbers would be -1 and 7. Finally, differentiate the squares.

5m\left(m-1\right)\left(m+7\right)

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Pencils cost $.10 and erasers cost $0.25. steve bought 5 more pencils than erasers. he spent a total of $1.55. how many erasers
ad-work [718]

Answer:

Let x be the number of pencils Steve bought.

Let y be the number of erasers Steve bought.

x=y+5

0.1x + 0.25y = 1.55

Solving the system, our answer is: (8, 3)

So, she bought 3 erasers.

Let me know if this helps!

5 0
3 years ago
Mrs. Lee works 4y hours each day from Monday to Friday. She works (4y-4) hours on Saturday.
7nadin3 [17]

Answer:

24y-4

Step-by-step explanation:

4y*5=20y

20y+4y-4= 24y-4

5 0
2 years ago
Please help me answer this please!!
Assoli18 [71]
I think the answer is 15
8 0
3 years ago
1) The cost of constructing a path 5 m broad inside the boundary of a square lawn at Rs 36.25 per sq. metre is Rs 90625. What is
Svetach [21]

Let , side lawn is a.

Area of boundary is :

A=4\times5\times a\\\\A=20a\ m^2

Now, total cost is given by :

T=20a\times 36.25\\\\90625=725a\\\\a=125\ m

Area left is :

A'=a^2-20a\\\\A'=125^2-20\times 125\ m^2\\\\A'=13125\ m^2

Price to empty space with turfs is :

P=A'\times 20\\\\P=13125\times 20\\\\P=262500

Therefore, the cost of covering the empty space with turfs at the rate of Rs 20 per sq. metre is Rs 262500.

Hence, this is the required solution.

3 0
3 years ago
Can someone help me<br> 7 + 2h = 3 + 4h
STALIN [3.7K]

h = 2

7 + 2h = 3 + 4h

You must isolate the variable to solve using the order of operations, or PEMDAS.

4 = 2h

Subtract 3 from both sides of the equation, and subtract 2h from both sides of the equation.

\frac{4}{2}  = h

Divide both sides of the equation by 2.

h = 2

7 0
3 years ago
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