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viktelen [127]
3 years ago
9

Multiply and write in standard form. (2x+4) (x2−8x+7)

Mathematics
2 answers:
Naddika [18.5K]3 years ago
6 0

Answer:

{2x}^{3}  -  {12x}^{2}  - 18x + 28

Step-by-step explanation:

(2x + 4)( {x}^{2}  - 8x + 7) \\  =  {2x}^{3}  - {16x}^{2}  + 14x +  {4x}^{2}  - 32x + 28 \\  =  {2x}^{3}  -  {12x}^{2}  - 18x + 28

astraxan [27]3 years ago
4 0

Answer:

2x³ - 12x² - 18x + 28

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, that is

2x(x² - 8x + 7) + 4(x² - 8x + 7) ← distribute both parenthesis

= 2x³ - 16x² + 14x + 4x² - 32x + 28 ← collect like terms

= 2x³ - 12x² - 18x + 28 ← in standard form

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Answer:

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Step-by-step explanation:

C=r(5-d)/y

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Divide each side by r

Cy/r=r(5-d)/r

Cy/r=(5-d)

Subtract 5 from each side

Cy/r - 5 = 5-d-5

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Step-by-step explanation:

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Now we can solve

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