Use this formula, it’s called distance formula
Solution: The speed of old freight train is 0.5 miles per minute and the speed of new dart express train is 1.5 miles per minute.
Explanation:
Let the speed of old freight train is x miles per minute and the speed of new dart express train is y miles per minute.
It is given that the speed of the dart express train is three times faster than the freight train. So, it can be written as,
....(1)
The trains are moving towards the opposite directions, therefore the distance between them is increased at the speed of
miles per minute.

The distance between both train in 15 minutes is represented by
.
According to the given information the distance between trains is 30 miles in 15 minutes.


Use equation (1) and put 



Put this value in equation (1), to find the value of y.


Therefore, the The speed of old freight train is 0.5 miles per minute and the speed of new dart express train is 1.5 miles per minute.
Answer:
Step-by-step explanation:
The first one is actually 0 I think. The instantaneous ROC at x=1 should also be 0. The last one should be correct.
Basically, the ROC for the first one is 0 because the y value at the start and end of the interval is the same, so the change is the same. However, for the instantaneous ROC at x = 0, you look at the graph and realize that if you find the derivative at that point, it is 0.
Basically expand
use FOIL (a way to remember distributive property)
first outer inner last
that is th eorder to multiply them
First: x times 2x=2x²
Outer: x tmes 9=9x
Inner: -8 times 2=-16x
last: -8 times 9=-72
add them
2x²+9x-16x-72
2x²-7x-72
9514 1404 393
Answer:
- R'(-2, 2)
- F'(2, 2)
- G'(-2, -2)
Step-by-step explanation:
It can be useful to keep a list of the 90° rotation transformations.
(x, y) ⇒ (-y, x) . . . . . . 90° CCW, 270° CW
(x, y) ⇒ (-x, -y) . . . . . . 180°
(x, y) ⇒ (y, -x) . . . . . . . 270° CCW, 90° CW
__
1) (x, y) ⇒ (-x, -y) . . . . 180°
R(2, -2) ⇒ R'(-2, 2)
__
2) (x, y) ⇒ (-y, x) . . . . 90°
F(2, -2) ⇒ F'( 2, 2)
__
3) (x, y) ⇒ (y, -x) . . . . 270°
G(2, -2) ⇒ G'(-2, -2)