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katovenus [111]
3 years ago
10

The y-intercept of a line has the same value as its gradient. If this line cuts the curve y =

x%5E%7B3%7D" id="TexFormula1" title="x^{3}" alt="x^{3}" align="absmiddle" class="latex-formula"> – 2x^{2} – 3x – 8 at x = 3, find the equation of the line.
Select one:


a. 2x − y + 2 = 0


b. 2x + y + 2 = 0


c. 2x + y − 2 = 0


d. None of these
Mathematics
2 answers:
Vlada [557]3 years ago
8 0
I think the answer will be D because I can’t find an answer for this question.
Aliun [14]3 years ago
7 0

Answer:

B. 2x+y+2+=0

Step-by-step explanation:

Given: x=3

First: you substitute for x in y=x^3-2x^2-3x-8

y=(3)^3-2(3)^2-3(3)-8

y=-8

Now all you have to do is plug y in each of the answers until you get 3 for x.

A. 2x-(-8)+2=0

   2x+10=0

   2x=-10

   x=-5

B. 2x+(-8)+2=0

   2x-6=0

   2x=6

   x=3

C. 2x+(-8)-2=0

   2x-10=0

   2x=10

   x=5

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Step-by-step explanation:

hi

personally this is how i would do this question but there are other ways.

i would start off by seeing how many sundays there are in the month (which is 5) then the number of other days which is 25. i'd then multiply 5 by 510 which is 2550. add that to 240 times 25 (which is 6000) and all of that together is 8550. divide that by the number of the days in the month (30) and then you'll get the daily avergae for the month

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