The y-intercept of a line has the same value as its gradient. If this line cuts the curve y = x%5E%7B3%7D" id="TexFormula1" title="x^{3}" alt="x^{3}" align="absmiddle" class="latex-formula"> – 2
– 3x – 8 at x = 3, find the equation of the line.
Select one:
a. 2x − y + 2 = 0
b. 2x + y + 2 = 0
c. 2x + y − 2 = 0
d. None of these
2 answers:
I think the answer will be D because I can’t find an answer for this question.
Answer:
B. 2x+y+2+=0
Step-by-step explanation:
Given: x=3
First: you substitute for x in y=x^3-2x^2-3x-8
y=(3)^3-2(3)^2-3(3)-8
y=-8
Now all you have to do is plug y in each of the answers until you get 3 for x.
A. 2x-(-8)+2=0
2x+10=0
2x=-10
x=-5
B. 2x+(-8)+2=0
2x-6=0
2x=6
x=3
C. 2x+(-8)-2=0
2x-10=0
2x=10
x=5
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– 3x – 8 at x = 3, find the equation of the line.
