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slamgirl [31]
3 years ago
14

Solve the equation x + 0.7 = 1 - 0.2x in two different ways.Then check your answer.Show your work!

Mathematics
1 answer:
expeople1 [14]3 years ago
6 0
Simplifying
x + 0.7 = 1 + -0.2x

Reorder the terms:
0.7 + x = 1 + -0.2x

Solving
0.7 + x = 1 + -0.2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '0.2x' to each side of the equation.
0.7 + x + 0.2x = 1 + -0.2x + 0.2x

Combine like terms: x + 0.2x = 1.2x
0.7 + 1.2x = 1 + -0.2x + 0.2x

Combine like terms: -0.2x + 0.2x = 0.0
0.7 + 1.2x = 1 + 0.0
0.7 + 1.2x = 1

Add '-0.7' to each side of the equation.
0.7 + -0.7 + 1.2x = 1 + -0.7

Combine like terms: 0.7 + -0.7 = 0.0
0.0 + 1.2x = 1 + -0.7
1.2x = 1 + -0.7

Combine like terms: 1 + -0.7 = 0.3
1.2x = 0.3

Divide each side by '1.2'.
x = 0.25

Simplifying
x = 0.25

I only know 1 way.
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Please help me!!!!!!!!!!!!!!
arsen [322]

Ans

184 sq meter

Step-by-step explanation:

Area of the cuboid box = (2*FA)+(2*SA)+(2*TA)

Where FA= Front face area

SA= Side face area

TA= top face are

Here FA= length * breadth = 10*6=60 sq meter

SA= 10*2= 20 sq meter

TA= 6*2= 12 sq meter

So area of box= 2*60+2*20+2*12= 184 sq meter

7 0
3 years ago
What is a reasonable estimate for the problem? 3 3/4 x -2/5
Airida [17]

Answer:

You can not break that down any further if x does not equal anything and the equation is not equal to anything.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Two major automobile manufacturers have produced compact cars with engines of the same size. We are interested in determining wh
Molodets [167]

Answer:

(A) The mean for the differences is 2.0.

(B) The test statistic is 1.617.

(C) At 90% confidence the null hypothesis should not be rejected.

Step-by-step explanation:

We are given that a random sample of eight cars from each manufacturer is selected, and eight drivers are selected to drive each automobile for a specified distance.

The following data (in miles per gallon) show the results of the test;

Driver         Manufacturer A               Manufacturer B

   1                      32                                       28

  2                      27                                       22

  3                      26                                       27

  4                      26                                       24

  5                      25                                       24

  6                      29                                       25

  7                       31                                       28

  8                      25                                       27

Let \mu_1 = mean MPG for the fuel efficiency of Manufacturer A brand

\mu_2 = mean MPG for the fuel efficiency of Manufacturer B brand

SO, Null Hypothesis, H_0 : \mu_1-\mu_2=0  or  \mu_1= \mu_2    {means that there is a not any significant difference in the mean MPG (miles per gallon) when testing for the fuel efficiency of these two brands of automobiles}

Alternate Hypothesis, H_A : \mu_1-\mu_2\neq 0  or  \mu_1\neq  \mu_2   {means that there is a significant difference in the mean MPG (miles per gallon) for the fuel efficiency of these two brands of automobiles}

The test statistics that will be used here is <u>Two-sample t test statistics</u> as we don't know about the population standard deviations;

                      T.S.  = \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }  ~ t__n__1+_n__2-2

where, \bar X_1 = sample mean MPG for manufacturer A = \frac{\sum X_A}{n_A} = 27.625

\bar X_2 = sample mean MPG for manufacturer B =\frac{\sum X_B}{n_B} = 25.625

s_1 = sample standard deviation for manufacturer A = \sqrt{\frac{\sum (X_A-\bar X_A)^{2} }{n_A-1} } = 2.72

s_2 = sample standard deviation manufacturer B = \sqrt{\frac{\sum (X_B-\bar X_B)^{2} }{n_B-1} } = 2.20

n_1 = sample of cars selected from manufacturer A = 8

n_2 = sample of cars selected from manufacturer B = 8

Also, s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2} }   =  \sqrt{\frac{(8-1)\times 2.72^{2}+(8-1)\times 2.20^{2}  }{8+8-2} }  = 2.474

(A) The mean for the differences is = 27.625 - 25.625 = 2

(B) <u><em>The test statistics</em></u>  =  \frac{(27.625-25.625)-(0)}{2.474 \times \sqrt{\frac{1}{8}+\frac{1}{8}  } }  ~  t_1_4

                                     =  1.617

(C) Now at 10% significance level, the t table gives critical values between -1.761 and 1.761 at 14 degree of freedom for two-tailed test. Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that there is a not any significant difference in the mean MPG (miles per gallon) when testing for the fuel efficiency of these two brands of automobiles.

5 0
3 years ago
How to I write 1/8 without using a fraction bar ( it wants me to use exponents)
oksano4ka [1.4K]
2^-3

two raised to negative three
6 0
3 years ago
Read 2 more answers
Simplify:<br> The square root of p squared
Evgen [1.6K]

Answer:

p

Step-by-step explanation:

\sqrt{p^2} = p

3 0
2 years ago
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