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3 years ago

Simplify: 1. 4³×4⁶/4⁴2. y⁴×y⁶/y⁸help me plzzzz

Mathematics

1 answer:

rjkz [21]3 years ago

4 0

Step-by-step explanation:

${4}^{ 3} \times {4}^{6} \div 4^{4} \\ {4}^{3 + 6 - 4} \\ {4}^{5}$

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4 years ago

In a large school, it was found that 77% of students are taking a math class, 74% of student are taking an English class, and 70

Iteru [2.4K]

Answer:

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

Step-by-step explanation:

We solve this question working with the probabilities as Venn sets.

I am going to say that:

Event A: Taking a math class.

Event B: Taking an English class.

77% of students are taking a math class

This means that $P(A) = 0.77$

74% of student are taking an English class

This means that $P(B) = 0.74$

70% of students are taking both

This means that $P(A \cap B) = 0.7$

Find the probability that a randomly selected student is taking a math class or an English class.

This is $P(A \cup B)$ , which is given by:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

$P(A \cup B) = 0.77 + 0.74 - 0.7 = 0.81$

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

Find the probability that a randomly selected student is taking neither a math class nor an English class.

This is

$1 - P(A \cup B) = 1 - 0.81 = 0.19$

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

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3 years ago

The square below represents one whole. What percent is represented by the shaded area?

Allisa [31]

Answer:

6%. There are 100 blocks, and 6 are shaded. 6 out of 100 is 6%

Hope this helps!

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3 years ago

Read 2 more answers

Simplify: 1. 4³×4⁶/4⁴2. y⁴×y⁶/y⁸help me plzzzz​

Simplify: 1. 4³×4⁶/4⁴2. y⁴×y⁶/y⁸help me plzzzz