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iVinArrow [24]
2 years ago
12

AB = 6cm , AC = 12cm Calculate the length of CD Give your answer to 3 significant figures

Mathematics
1 answer:
Len [333]2 years ago
6 0

Answer:

144-36=108

Square root 108 = 10.4cm (cb)

Soh Cah toa

Sin(55) =o/h

=10.4/h

xh

H x sin55 =10.4

÷sin55

H= 10.4/sin55

H=12.7cm

CD is 12.7cm to 3 s.f.

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3 years ago
Propane has a heat energy of 2,470 BTU/ft cubed. How much energy can a propane tank with a volume of 43.7 ft cubed produce?
professor190 [17]

Answer: 107939\ BTU

Step-by-step explanation:

Given

Propane produced heat energy of 2470\ BTU/ft^3

The volume of the tank is 43.7\ ft^3

The energy produced by this propane tank is

\Rightarrow 2470\times 43.7=107939\ BTU

4 0
2 years ago
What is the equation for this table? 30 points!!!!
Marat540 [252]
That was made up?cz I tried to solve it and I kept getting different #s
5 0
3 years ago
Twice a certain whole number subtracted from 3 times the square of the number leaves 133. Find the number
user100 [1]

Answer:

7

Step-by-step explanation:

"a certain whole number" is a number that we don't know, so pick a variable, let's use n

"Twice" means two times, so we'll use 2n for this.

"subtracted from" means the 2n will be AFTER the minus sign.

____ - 2n

What goes in front? "3 times the square of the number" 3n^2

Now we have 3n^2 - 2n

Lastly, we see the result is 133. So this gives us:

3n^2 - 2n = 133 To solve, subtract 133 from both sides of the equation.

3n^2 -2n - 133 = 0 Next FACTOR.

(3n + 19)(n - 7) = 0

3n+19=0 and n-7=0

n=-19/3 and n=7

Since we are looking for a whole number choose n=7

6 0
2 years ago
The data sets show the years of the coins in two collections. Derek's collection: 1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910
KATRIN_1 [288]

Answer:

Derek's collection :

Mean= 1929

Median= 1930

Range= 54

IQR = 48

MAD= 23.75

Paul's collection:

Mean= 1929

Median= 1929.5

Range= 15

IQR = 6

MAD= 3.5

Step-by-step explanation:

1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910

Mean is given by:

(1950+1952+ 1908+1902+1955+1954+1901+1910)/8

=1929

absolute deviation from mean is:

|1950-1929|= 21

|1952-1929|= 23

|1908-1929|= 21

|1902-1929|= 27

|1955-1929|= 26

|1954-1929|= 25

|1901-1929|= 28

|1910-1929|= 19

from the mean of absolute deviation gives the MAD of the data i.e.

(21+23+21+27+26+25+28+`9)/8

23.75

 

:arrange the given data to get the range and median

   1901   1902    1908   1910    1950  1952    1954   1955

The minimum value is: 1901

Maximum value is: 1955

Range is: Maximum value-minimum value

         Range=1955-1901

Range= 54

median is (1910+1950)/2

1930

   the lower set of data=

  1901   1902    1908   1910

first quartile becomes

1902+1908)/2

Q1=1905

and upper set of data is:

1950  1952    1954   1955

we find the median of the  upper quartile or third quartile is:

1952+1954)/2=1953

Q3-Q1=1953-1905=

IQR=48

 

Paul's collection:

1929, 1935, 1928, 1930, 1925, 1932, 1933, 1920

Mean is given by:

1929+1935+ 1928+ 1930+ 1925+ 1932+1933+1920)/8

1929

absolute deviation from mean is:

|1929-1929|=0

|1935-1929|= 6

|1928-1929|= 1

|1930-1929|= 1

|1925-1929|= 4

|1932-1929|= 3

|1933-1929|= 4

|1920-1929|= 9

Hence, we get:

MAD=0+6+1+1+4+3+4+9/8

28/8

3.5

arrange the data in ascending order we get:

1920   1925   1928   1929   1930   1932   1933   1935  

Minimum value= 1920

Maximum value= 1935

Range=  15 (  1935-1920=15 )

The median is between 1929 and 1930

Hence, Median= 1929.5

Also, lower set of data is:

1920   1925   1928   1929  

the first quartile or upper quartile is

1925+1928/2

1926.5

and the upper set of data is:

1930   1932   1933   1935  

We have

1932+1933)/2

1932.5

IQR is calculated as:

Q3-Q1

6

7 0
3 years ago
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