5530 mm is 553 cm and 5.53 m.
Answer:
The new volume is 20litres
Step-by-step explanation:
This problem bothers on the expansion of gases
According to Boyle's law
The volume of a given mass of gas at constant temperature is inversely proportional to the pressure
P∝1/v
Pv= constant
Given data
P1= 1.5atm
v1 = 10 litter
P2=0.75atm
v2=?
Applying P1v1= P2v2
v2= P1v1/P2
v2= 1.5*10/0.75
v2= 15/0.75
v2= 20litres
Answer:
a) 2,650%
b) 27,400%
c) 164,900%
Step-by-step explanation:
We want to measure the percentage we would have to increase the typical value to obtain the values given in a), b) and c).
But 0.2 increased in x% equals
0.2 + 0.2(x/100) =0.2(1+x/100)
So, if we want to increase 0.2 in x%, we must multiply it by (1+x/100)
a)
We need to find the value of x such that
0.2(1+x/100) = 5.5 ⇒ (1+x/100)=5.5/0.2 ⇒ 1+x/100=27.5
⇒ x/100=26.5 ⇒ x=2,650%
b)
0.2(1+x/100) = 55 ⇒ (1+x/100)=55/0.2 ⇒ 1+x/100=275
⇒ x/100=274 ⇒ x=27,400%
c)
5.5 min = 5.5*60 s = 330
0.2(1+x/100) = 330 ⇒ (1+x/100)=330/0.2 ⇒ 1+x/100=1,650
⇒ x/100=1,649 ⇒ x=164,900%
Answer:
yes
Step-by-step explanation:
