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ahrayia [7]
3 years ago
7

What is the measure of angle 2?

Mathematics
2 answers:
kirza4 [7]3 years ago
8 0

Answer:

Step-by-step explanation:

∠2 = 55°

Vertically opposite angles are equal.

guapka [62]3 years ago
3 0

Answer:

∠ 2 = 55°

Step-by-step explanation:

∠ 2 and 55° are vertical angles and congruent, thus

∠ 2 = 55°

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Andrea is told that the means of two groups in a study were statistically significant. She knows the means and standard deviatio
salantis [7]

Answer:

Cohen's D

Step-by-step explanation:

Cohen's D is a statistic that measures effect size. It shows standardised difference between 2 means.

Effect size is defined as how large the effect of a something is or its magnitude.

Cohen's D works effectively when the sample is >50 (that is for large samples). However a correction factor can be used to make results from small samples more accurate

The formular for Cohen's D is:

D = (mean1 - mean2) ÷ (√({standard deviation1}^2 + {standard deviation 2}^2)/2)

This is the most appropriate method in the given scenario

5 0
3 years ago
1
stellarik [79]

Answer:

there are 33 marbles

Step-by-step explanation:

100÷3

3 0
3 years ago
7(3r - 1) - (r + 5) = -52<br><br> Please step by step help
MrMuchimi
7(3r-1)-(r+5)=-52

21r-7-r-5=-52

21r-r-5-7=-52

20r-12=-52

Add 12 to both sides

20r=-40

Divide by 20

r=-2
4 0
4 years ago
Read 2 more answers
What is the answer to this?
taurus [48]

10 total marbles:

 1st pick = 2/10 = 1/5

2nd pick = 1/9

overall probability = 1/5 * 1/9 = 1/45

7 0
4 years ago
Simplify the expression using trigonometric identities: sec (–θ) – cos θ.
ololo11 [35]

Answer:

sin θ . tan θ

Step-by-step explanation:

Note : -

sec ( - θ ) = sec θ

Formula / Identity : -

sec θ = 1 / cos θ

sec ( - θ ) - cos θ

= [ 1 / cos θ ] - cos θ

{ LCM = cos θ }

= [ 1 / cos θ ] - [ cos²θ / cos θ ]

= [ 1 - cos²θ ] / cos θ

{ 1 - cos²θ = sin²θ }

= sin²θ / cos θ

{ sin²θ = sin θ . sin θ }

= sin θ . sin θ / cos θ

{ sin θ / cos θ = tan θ }

= sin θ . tan θ

Hence, simplified.

4 0
3 years ago
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