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Agata [3.3K]
3 years ago
12

A cone has a lateral area of 108 in2 and a base area of 48 in2. What is the surface area of the cone? A. 60 in2 B. 140 in2 C. 12

8 in2 D. 156 in2
Mathematics
1 answer:
Andrei [34K]3 years ago
5 0
Based on the given data, the following formula will be useful;
Area of the base, A = pi*r^2
Lateral Area, A(l) = pi*r*sqrt of h^2 + r^2
Surface Area, A(s) = pi*r*(r+sqrt of h^2 + r^2)
Based on the given area of the base, the radius can be calculated and is equal to 3.9088 in. Based on the given lateral area, the h or the lateral edge can be calculated and is equal to 7.8785 in. Given all the information needed, and directly substituting to the above formula for surface area, SA is equal to 156 in^2 (option D)
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Please show work 7r + 21 = 49r
gulaghasi [49]

Answer:

1/2 = r

Step-by-step explanation:

7r + 21 = 49r

Subtract 7r from each side

7r-7r + 21 = 49r-7r

21 = 42r

Divide each side by 2

21/42 = 42r/42

1/2 = r

5 0
2 years ago
Read 2 more answers
sum of two numbers is 39. the greater number is 7 more than the smaller number. ( set up an equation )
pochemuha
Let x be the unknown number

2x +7 = 39

2x+7-7 = 39-7

2x = 32

2x/2 = 32/2

x=16

You use the balance method to solve. First, you cancel the +7 by subtracting the 7 ON BOTH SIDES to balance the equation.. After that, you are left with 2x, where you will need to isolate the x by dividing by 2 ON BOTH SIDES to balance it.

Hope this helps
3 0
2 years ago
en un colegio mixto hay x estudiantes distribuidos en c cursos. Si hay m niños por curso, ¿Cuantas niñas hay en el colegio?
Tomtit [17]

La ecuación que nos dice cuantas niñas hay en el colegio es:

A = x - c*m

¿Como encontrar una expresión para la cantidad de niñas?

Sabemos que hay un total de x estudiantes, definimos las variables:

  • A = cantidad total de niñas
  • B = cantidad total de niños.

Entonces tenemos A + B = x

Tambien sabemos que los estudiantes estan divididos en c cursos, de tal forma que hay m niños por curso.

Entonces c por m es igual a la cantidad total de niños:

c*m = B

Reemplazando esto en la ecuación de arriba podemos obtener:

A + c*m = x

A = x - c*m

Esta es la ecuación que nos da el numero total de niñas en el colegio.

Sí quieres aprender más sobre ecuaciones, puedes leer:

brainly.com/question/18168483

4 0
1 year ago
REAL LIFE A cylindrical hazardous waste container has a diameter of 1.5 feet and a height of 1.6 feet. Abo
aivan3 [116]

Answer:

It can hold up to 1.256ft^3 of waste

<em></em>

Step-by-step explanation:

Given

D = 1.5ft -- Diameter

h = 1.6ft -- height

Required

Determine the amount of waste it can hold

This simply means that we calculate the volume of the cylindrical container.

And this is calculated using:

Volume = \pi r^2h

Where

\pi = 3.14

and

r = \frac{D}{2}

r = \frac{1.5}{2}

r = 0.75

So, we have:

Volume = 3.14 * 0.5^2 * 1.6

Volume = 1.256ft^3

<em>Hence, it can hold up to </em>1.256ft^3<em> of waste</em>

3 0
3 years ago
Richard has just been given an l0-question multiple-choice quiz in his history class. Each question has five answers, of which o
myrzilka [38]

Answer:

a) 0.0000001024 probability that he will answer all questions correctly.

b) 0.1074 = 10.74% probability that he will answer all questions incorrectly

c) 0.8926 = 89.26% probability that he will answer at least one of the questions correctly.

d) 0.0328 = 3.28% probability that Richard will answer at least half the questions correctly

Step-by-step explanation:

For each question, there are only two possible outcomes. Either he answers it correctly, or he does not. The probability of answering a question correctly is independent of any other question. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Each question has five answers, of which only one is correct

This means that the probability of correctly answering a question guessing is p = \frac{1}{5} = 0.2

10 questions.

This means that n = 10

A) What is the probability that he will answer all questions correctly?

This is P(X = 10)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{10,10}.(0.2)^{10}.(0.8)^{0} = 0.0000001024

0.0000001024 probability that he will answer all questions correctly.

B) What is the probability that he will answer all questions incorrectly?

None correctly, so P(X = 0)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074

0.1074 = 10.74% probability that he will answer all questions incorrectly

C) What is the probability that he will answer at least one of the questions correctly?

This is

P(X \geq 1) = 1 - P(X = 0)

Since P(X = 0) = 0.1074, from item b.

P(X \geq 1) = 1 - 0.1074 = 0.8926

0.8926 = 89.26% probability that he will answer at least one of the questions correctly.

D) What is the probability that Richard will answer at least half the questions correctly?

This is

P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{10,5}.(0.2)^{5}.(0.8)^{5} = 0.0264

P(X = 6) = C_{10,6}.(0.2)^{6}.(0.8)^{4} = 0.0055

P(X = 7) = C_{10,7}.(0.2)^{7}.(0.8)^{3} = 0.0008

P(X = 8) = C_{10,8}.(0.2)^{8}.(0.8)^{2} = 0.0001

P(X = 9) = C_{10,9}.(0.2)^{9}.(0.8)^{1} \approx 0

P(X = 10) = C_{10,10}.(0.2)^{10}.(0.8)^{0} \approx 0

So

P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.0264 + 0.0055 + 0.0008 + 0.0001 + 0 + 0 = 0.0328

0.0328 = 3.28% probability that Richard will answer at least half the questions correctly

8 0
3 years ago
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