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pishuonlain [190]
3 years ago
10

Sweet T has 2 orange picks for every 5 green. If there are 12 picks in all how many picks are orange

Mathematics
1 answer:
e-lub [12.9K]3 years ago
4 0
There are eight orange picks.
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Wanting someone to help me with the procedures<br>n²+n=120<br><br>​
Natali [406]
N^2 + n - 120 = 0

Quadratic formula
a = 1, b = 1, c = -120
n = [-1 plus or minus root(1^2 - 4(1)(-120))] / 2(1)
n = (-1 plus or minus root481)/2
n =(approximately) 10.5 or -11.5
4 0
3 years ago
The rate at which a professional tennis player used carbohydrates during a strenuous workout was found to be 1.7 grams per minut
Alex787 [66]

Answer:

<em>m=1.7</em>

<em>C=68 gr</em>

Step-by-step explanation:

<u>Function Modeling</u>

We are given a relationship between the carbohydrates used by a professional tennis player during a strenuous workout and the time in minutes as 1.7 grams per minute. Being C the carbohydrates in grams and t the time in minutes, the model is

C=1.7t

The slope m of the line is the coefficient of the independent variable, thus m=1.7

The graph of C vs t is shown in the image below.

To find how many carbohydrates the athlete would use in t=40 min, we plug in the value into the equation

C=1.7\cdot 40=68\ gr

8 0
3 years ago
Can someone help me with these questions
fredd [130]

Answer:

Do your homework by yourself

Step-by-step explanation:

4 0
2 years ago
You have a six-sided die that you roll once. Let Ri denote the event that the roll is i. Let G j denote the event that the roll
Misha Larkins [42]

Answer:

a. P (R3 | G1)=\frac{1}{5}

b. P (R6| G3)= \frac{1}{3}

c. P(G3|E)=\frac{2}{3}

d. P (E|G3)=\frac{2}{3}

Step-by-step explanation:

The sample space associated with the random experiment of throwing a dice is is the equiprobable space {R1, R2, R3, R4, R5, R6}. Then,

a. The conditional probability that 3 is rolled given that the roll is greater than 1? P (R3 | G1) = \frac{P (R3\bigcap G1)}{P(G1)} = \frac{1/6}{5/6} = \frac{1}{5}

b. What is the conditional probability that 6 is rolled given that the roll is greater than 3? P (R6| G3) = \frac{P (R6\bigcap G3)}{P(G3)} = \frac{1/6}{3/6} = \frac{1}{3}

c. What is P [GIE], the conditional probability that the roll is greater than 3 given that the roll is even? P(G3|E) = \frac{P (G3\bigcap E)}{P(E)} = \frac{2/6}{3/6} = \frac{2}{3}

d. Given that the roll is greater than 3, what is the conditional probability that the roll is even? P (E|G3) = \frac{P (E\bigcap G3)}{P(G3)} = \frac{2/6}{3/6} = \frac{2}{3}

6 0
3 years ago
Here are two spinners
dsp73
Ok? what is the question
7 0
2 years ago
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