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Natalka [10]
2 years ago
11

Expand using identities: (i) (2x- 5y)² (ii) (11a + 2) (11a – 2) (iii) (7m + 3) (7m + 3)

Mathematics
1 answer:
natulia [17]2 years ago
7 0

Answer:

Step-by-step explanation:

(2x-5y)^2

(2x-5y)(2x-5y)

4x^2-10xy-10xy+25y^2

4x^2-20xy+25y^2

------------------------------

(11a+2)(11a-2)

121a^2+22a-22a-4

121a^2-4

------------------------------

(7m+3)(7m+3)

49m^2+21m+21m+9

49m^2+42m+9

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A high speed train travels a distance of 503 km in 3 hours.
tensa zangetsu [6.8K]

The average speed, in km/minute, of the train is 2.79 km/minute

<h3>Calculating average speed </h3>

From the question, we are to calculate the average speed in km/minute

From the given information,

Distance travelled = 503 km

Time taken = 3 hours = 3 × 60 minutes = 180 minutes

Using the average speed formula,

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∴ Average speed of the train = 503 / 180

Average speed of the train = 2.79 km/minute

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The factor of the polynomial, the area of the pool and the simplified expression are all algebraic expressions

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The polynomial is given as:

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Factor out 2

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Factorize

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Factor out x + 3

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2x^3 + 6x^2 + 6x + 18 = (2x^2 + 6)(x + 3)

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The given parameters are:

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The expression is given as:

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