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ivolga24 [154]
3 years ago
8

Please help me and correct answer gets brainliest

Mathematics
1 answer:
ahrayia [7]3 years ago
8 0

Answer:

= 42 square feet

Step-by-step explanation:

33 square feet + 3 square feet + 6 square feet

<em><u>= 42 square feet</u></em>

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Help plzzz!! Marking most Brainly;)
kolezko [41]

Answer:

D it

Step-by-step explanation:

We have two equations, A quadratic and a linear equation.

The domain of a linear equation and quadratic equation is all real numbers but since it dealing with time we must make sure the roots or x-intercepts is positive.

Looking at the quadratic equation, we can use the discramnt formula to see if all roots are positve.

b {}^{2} - 4ac

{ - 6}^{2}  - 4(1)(8.75)

36 - 35 = 1

The discramnt is greater than zero so there is two distinct real roots. So let check if they are positve

If you graph the equation, it intercepts at two positve roots so it is D

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3 years ago
PLEASE HELP ME!!!
jeyben [28]

Answer:

B.intrest fees

Step-by-step explanation:

3 0
3 years ago
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Fanning + medal
lubasha [3.4K]
The Greatest Common Factor of the given expression should be that expression that can divide both. First, factor both expression,
           x^4 = (x³)(x)      and x³ = (x³)(1)
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3 years ago
Read 2 more answers
A square postage stamp has area 1240 mm^2 about how long is each side?
Shtirlitz [24]
Sq.root of 1240 is approx 35 mm
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3 years ago
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Natasha2012 [34]

As we know that the standard equation of circle is {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}} , where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>

Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

{:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}

{:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}

{:\implies \quad \sf 9+16=r^{2}}

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>

Now , putting values in our standard equation ;

{:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

8 0
2 years ago
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