Answer:
Area 
square units
units
units
Step-by-step explanation:
In a right triangle the altitude drawn to the hypotenuse is the geometric mean of the segments at which this altitude divides the hypotenuse.
So,
a. The area of the triangle ABC is
b. The legs of the right triangle are geometric means of the segment adjacent to this leg and the hypotenuse, so
Answer:
Jenny is wrong the correct answer is x²+ 4 - 4 x.
Step-by-step explanation:
Given that
(x-2)³∕x-2
(x-2)³∕(x-2) =(x-2) (x-2)²∕(x-2)
(x-2)³∕(x-2) = (x-2)²
As we know that
(a-b)² = a²+b² - 2 ab
So
(x-2)² = x²+ 2² - 2 ˣ 2 ˣ x = x²+ 4 - 4 x
(x-2)² = x²+ 4 - 4 x
It means that
(x-2)³∕(x-2) = (x-2)² = x²+ 4 - 4 x
So Jenny is wrong the correct answer is x²+ 4 - 4 x.
The function is
f(x) = (1/3)x² + 10x + 8
Write the function in standard form for a parabola.
f(x) = (1/3)[x² + 30x] + 8
= (1/3)[ (x+15)²- 225] + 8
= (1/3)(x+15)² -75 + 8
f(x) = (1/3)(x+15)² - 67
This is a parabola with vertex at (-15, -67).
The axis of symmetry is x = -15
The curve opens upward because the coefficient of x² is positive.
As x -> - ∞, f -> +∞.
As x -> +∞, f -> +∞
The domain is all real values of x (see the graph below).
Answer: The domain is (-∞, ∞)
3, 6, 9, 12, 15
5, 10, 15
1/3 = 5/15
3/5 = 9/15
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You need to multiply the two numbers. Or you can use long addition.
