Which explanation can be used to derive the formula for the circumference of a circle?.

Four members of a relay team evenly split the distance of a race. Each person ran more than 100 meters. Which inequality can be

sergejj [24]

Answer:

The total distance the group ran can be represented by d > 400 m

Step-by-step explanation:

The total distance the group ran can be got by summing up all the individual distances ran by each athlete.

Let the distance the first athlete ran be x

from the question, we know that x >100 m

since all four athletes ran the same distance, the total distance run , d will be four times the distance ran by an athlete.

d > 4 X 100

d > 400 m

7 0

4 years ago

Read 2 more answers

Please help me, so I can help my son

Grace [21]

1:a would be 3. Subtract 9 & 6 to find 3. B= 7. Again 9-2 would help you find the answer. So then it would be 3+6=7+2.
2: 2+8 gets you 10. 10+5 gets you 15. 8+5 gets you 13. 2+13 gets you 15. So it’s 15=15.
3:7 needs to be changed into a fraction so, 7/1(1/7). Multiply across, you get 7/7, which gives you 1, so it’s 1=1.
4:I’m sorry I don’t know how to do this one
5:you multiply 3 and 6x, which gives you 18x. Then multiply 3 and 9y, and you get 27y. So then you have 18x+27y=18x+27y.
6: 15+0 gets you 15. So it’s 15=15.
Hope this helped. I’m not the best at explaining

4 0

4 years ago

An elementary school is in a growing suburb. The school’s principal estimates that the current enrollment of 750 students will i

HACTEHA [7]

Answer:

62.9% in ten years

Step-by-step explanation:

This type of growth corresponds to what is called an exponential growth, since in the expression for the number of students keep including the multiplication of the same factor as the years go by, Let's start by analyzing what happens the first year:

The initial enrollment of 750 is expected to grow by 5%, therefore after one year the enrollment should be:

After one year = Year_1 = 750 + 5% increase = $750+750*0.05=750(1+0.05)$

where we have used the decimal form of 5% as he factor 0.05 multiplying 750 (the initial enrollment) to give the increase.

After the second year, we consider a starting value of Year_1 enrollments that will increase another 5%, which gives: Year_2 = Year_1 + Year_1 * 0.05= Year_1 (1 + 0.05).

So replacing Year_1 by its original expression (750(1+0.05)) we notice that Year_2 = 750 * (1+0.05) * (1+0.05) = 750 * (1+0.05)^2

We can go on with this same reasoning and find that each year includes a new factor (1+0.05) to the new increasing enrollment.

At the end of 10 years, the number of enrollment will be:

$750*(1+0.05)^10=1221.67$