All categories

3 years ago

What is the equation in point-slope form of the line that passes through the point (4,-5) and has a slope of 2/3?

Mathematics

2 answers:

vazorg [7]3 years ago

6 0

Answer:

third one

Step-by-step explanation:

point-slope form is y - y1 = m(x - x1)

plug in values y -(-5) = 2/3(x - 4)

the double negative cancels out and becomes a positive

therefore y + 5 = 2/3(x - 4)

andre [41]3 years ago

3 0

Answer: I believe the correct answer is the last one but I’m not entirely sure, wait for someone else to answer.

Step-by-step explanation:

You might be interested in

Solve the equation for y: 6x-2y=14<br> Must show work

Marianna [84]

Answer:

i dont know this

Step-by-step explanation:

but what grade are u in?

3 0

3 years ago

Read 2 more answers

Please help me idk this

tangare [24]

Just subtract the amount he took.
Answer:
$4 \frac{1}{4}$

7 0

3 years ago

Read 2 more answers

: Use the image to complete the equation below.

Sati [7]

Vertically opposite angles are equal.

So,

(11y - 36)° = 63°

=> 11y - 36 = 63

6 0

3 years ago

Read 2 more answers

Solve 5x +3>19 what is it

tatyana61 [14]

Answer:

x > 3 1/5

Step-by-step explanation:

5x +3>19

Subtract 3 from each side

5x +3-3>19-3

5x >16

Divide each side by 5

5x/5 > 16/5

x > 16/5

x > 3 1/5

7 0

4 years ago

Which is the correct form of the quadratic formula? A) x = b ± b2 - 4ac a B) x = b ± b2 - 4ac 2a C) x = - b ± b2 - 4ac a D) x =

DochEvi [55]

That's pretty ill-formatted but the answer is D

$ax^2 + bx + c = 0$

has roots given by

$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Bonus quadratic formulas:

The Shakespeare Quadratic Formulas ( $2b$ or $-2b$ ) are:

$x^2 - 2bx + c \textrm{ has zeros at }x=b \pm \sqrt{b^2-c}$

$ax^2 - 2bx + c \textrm{ has zeros at }x=\frac 1 a( b \pm \sqrt{b^2-ac})$

4 0

4 years ago