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Ratling [72]
2 years ago
8

PLSS Someone plss help plss helppp plllsss Will mark brainliest!!!​

Mathematics
2 answers:
Ostrovityanka [42]2 years ago
6 0

Answer:

<em>( 6 , 8 ) </em>

Step-by-step explanation:

y = kx

k = \frac{y}{x}

( 3 , 4 )

k = \frac{4}{3}

\frac{4}{3} = \frac{8}{6} = \frac{12}{9} = ....

<em>( 6 , 8 )</em>

Umnica [9.8K]2 years ago
3 0
4,3 hope it help the top is 4 and the bottom is 3
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In DEF, C is the centroid if DM=45 , find DC and CM<br><br><br><br> DC= ? Units
IgorC [24]

Answer:

DC=30

CM=15

Step-by-step explanation:

Given

Triangle DEF with C centroid

DM=45 (length of median)

centroid divides median in the ratio 2:1(larger side at vertex)

⇒

DC=\frac{2}{3} \times DM=\frac{2}{3} \times 45= 2\times 15=30

⇒DC=30

DC+ CM=DM

30+CM=45

⇒CM=15

7 0
3 years ago
Use the Integral Test to determine whether the series is convergent or divergent
Inga [223]

Answer:

A. \sum_{n=1}^{\infty}\frac{n}{e^{15n}} converges by integral test

Step-by-step explanation:

A. At first we need to verify that the function which the series is related (\frac{n}{e^{15n}}) fills the necessary conditions to ensure that the test is effective.

*f(x) must be continuous or differentiable

*f(x) must be positive and decreasing

Let´s verify that f(x)=\frac{n}{e^{15n}} fills these conditions:

*Considering that eˣ≠0 for all x, the function f(x)=\frac{n}{e^{15n}} does not have any discontinuities, so it´s continuous

*Because eˣ is increasing:

      if a<b ,then eᵃ<eᵇ

      if 0<eᵃ<eᵇ ,then 1/eᵃ > 1/eᵇ

      if 1/eᵃ > 1/eᵇ and a<b, then a/eᵃ<b/eᵇ

  We conclude that f(x)=\frac{n}{e^{15n}} is decreasing

*Because eˣ is always positive and the sum is going from 1 to ∞, this show that f(x)=\frac{n}{e^{15n}} is positive in [1,∞).

Now we are able to use the integral test in f(x)=\frac{n}{e^{15n}} as follows:

\sum_{n=1}^{\infty}\frac{n}{e^{15n}}\ converges\ \leftrightarrow\ \int_{1}^{\infty}\frac{x}{e^{15x}}\ dx\ converges

Let´s proceed to integrate f(x) using integration by parts

\int_{1}^{\infty}\frac{x}{e^{15x}}\ dx=\int_{1}^{\infty}xe^{-15x}\ dx

Choose your U and dV like this:

U=x\ \rightarrow dU=1\\ dV=e^{-15x}\ \rightarrow V=\frac{-e^{-15x}}{15}

And continue using the formula for integration by parts:

\int_{1}^{\infty}Udv = UV|_{1}^{\infty} - \int_{1}^{\infty}Vdu

\int_{1}^{\infty}xe^{-15x}\ dx= \frac{-x}{15e^{15x}}|_{1}^{\infty} -\frac{-1}{15} \int_{1}^{\infty}e^{-15x}\ dx

\int_{1}^{\infty}xe^{-15x}\ dx= \frac{-x}{15e^{15x}}|_{1}^{\infty} -\frac{-1}{15}(\frac{-1}{15e^{15x}})|_{1}^{\infty}

\int_{1}^{\infty}xe^{-15x}\ dx= \frac{-x}{15e^{15x}}|_{1}^{\infty} -\frac{1}{225e^{15x}}|_{1}^{\infty}

Because we are dealing with ∞, we´d rewrite it as a limit that will help us at the end of the integral:

\int_{1}^{\infty}xe^{-15x}\ dx= \lim_{b \to{\infty}}(\frac{-x}{15e^{15x}}|_{1}^{b}-\frac{1}{225e^{15x}}|_{1}^{b})

\int_{1}^{\infty}xe^{-15x}\ dx= \lim_{b \to{\infty}} \frac{-b}{15e^{15b}}-\frac{1}{225e^{15b}}-(\frac{-1}{15e^{15}}-\frac{1}{225e^{15}})

\int_{1}^{\infty}xe^{-15x}\ dx= ( \lim_{b \to{\infty}} \frac{-b}{15e^{15b}}-\frac{1}{225e^{15b}})+\frac{1}{15e^{15}}(1-\frac{1}{15})

We only have left to solve the limits, but because b goes to  ∞ and it is in an exponential function on the denominator everything goes to 0

\lim_{b \to{\infty}} \frac{-b}{15e^{15b}}-\frac{1}{225e^{15b}} = 0

\int_{1}^{\infty}xe^{-15x}\ dx= \frac{1}{15e^{15}}(1-\frac{1}{15})

Showing that the integral converges, it´s the same as showing that the series converges.

By the integral test \sum_{n=1}^{\infty}\frac{n}{e^{15n}} converges

7 0
3 years ago
= 9x2 +9x -18,/<br> 3x +6
Ede4ka [16]

Answer:24+3x

Step-by-step explanation:

maybee i just used photomath

3 0
3 years ago
Please answer #1 for me only ! What is my Y for #1 , don't forget to graph !​
mart [117]
The table and the graph is shown in the following picture

7 0
3 years ago
Lisa ran 1/2 of a mile John R and 242 Mi what's girl ran further
julia-pushkina [17]

The fraction that has been given illustrates that the person who ran further is Jane.

<h3>How to solve fraction</h3>

Your information isn't complete. Therefore, an overview of the fraction will given.

Let's assume that Lisa ran 1/2 of a mile and Jane ran 3/4 of a mile. In order to know who ran more, you can convert the fraction to percentage.

This will be:

Lisa = 1/2 × 100 = 50%

Jane = 3/4 × 100 = 75%

Therefore, Jane ran more.

Learn more about fractions on:

brainly.com/question/78672

4 0
2 years ago
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