Speed=distance/time
suppose the distance of the first day is d, and the time is t
distance of the second day: d+0.17d=1.17d
time of the second day: t+0.2t=1.2t
speed of the second day: 1.17d/1.2t=0.975(d/t)=(1-0.025)(d/t)
so the speed of the second day is 2.5% slower than the first day.
Subtract 350 from both sides then divide both sides by 25.
(c-350)/25 = h
Answer:

Step-by-step explanation:
Given the expression
.
we have to find the simplest form of the expression.

=
=
=
which is the simplest form of the given expression.