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3 years ago

Is this median close to 10, 83.5 or 80?

Mathematics

2 answers:

kozerog [31]3 years ago

6 0

Answer:

Step-by-step explanation:

it's not quite on 85 so I assume it is on 83.5

Masja [62]3 years ago

5 0

It’s close to 83.5,

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Sadie computes the perimeter of a rectangle by adding the length, l , and width, w , and doubling this sum. Eric computes the pe

larisa [96]

a) P = 2(l+w) Sadie

P =2l+2w Eric

b) Sadie : P = 2(30+75) = 2(105) = 210

Eric: P = 2(30) +2(75) = 60+150 =210

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3 years ago

Please answer the questions below.

hoa [83]

Answer:

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Step-by-step explanation:

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3 years ago

Find the 53rd term of the arithmetic sequence<br> 27,11, -5

vivado [14]

Answer:

The 53rd term of this arithmetic sequence is -805.

Step-by-step explanation:

The general rule of an arithmetic sequence is the following:

$a_{n+1} = a_{n} + d$

In which d is the common diference between each term, that is, $d = a_{3} - a_{2} = a_{2} - a_{1}$ .

To find the nth term of the sequence, this equation can be written as:

$a_{n} = a_{1} + (n-1)d$

27,11, -5

So $a_{1} = 27, a_{2} - a_{1} = 11 - 27 = -16[/tex[tex]a_{n} = a_{1} + (n-1)d$

$a_{53} = a_{1} + (52)d = 27 + 52*(-16) = -805$

The 53rd term of this arithmetic sequence is -805.

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3 years ago

The number of typing errors made by a typist has a Poisson distribution with an average of three errors per page. If more than t

damaskus [11]

Answer:

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Poisson distribution with an average of three errors per page

This means that $\mu = 3$

What is the probability that a randomly selected page does not need to be retyped?

Probability of at most 3 errors, so:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498$

$P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494$

$P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240$

$P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240$

Then

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0498 + 0.1494 + 0.2240 + 0.2240 = 0.6472$

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

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3 years ago

What are convex polygnos

Archy [21]

Answer:

Step-by-step explanation:

Polygons (shapes made of straight lines) where no angle is greater than 180 degrees. If even one angle is greater than 180 then it is a concave polygon.

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4 years ago