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3 years ago

What is the answer ?

Mathematics

2 answers:

Softa [21]3 years ago

8 0

Answer:

353

Step-by-step explanation:

355-42=x-40

I just need to subtract 2 from 355 to get x because I subtracted 2 from 42 to get 40.

355-2=353=x

salantis [7]3 years ago

3 0

The answer is 353 :D

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Write the equation of the parabola in vertex form.

givi [52]

Answer: -9 = a(1 - 3)² + 3

Step-by-step explanation:

Vertex Form Equation:

y = a(x - h)² + k

vertex: (h, k) which means

h = 3

k = 3

because your vertex is (3, 3).

Your point is (1, -9) which is (x, y).

This means

x = 1

y = -9

Now, plug everything into your Vertex Form Equation:

-9 = a(1 - 3)² + 3

That’s your equation and final answer, but of course, if you need to, you can solve for a if you need to.

If a is positive, the parabola opens up. If a is negative, the parabola opens down.

Hope this helps!

3 0

3 years ago

PLEASE look at photo and help!

VMariaS [17]

It would be a a 6 by 5 inch rectangle, since the height is 6in and the width is 5in. Those are what would make up the cross section.

6 0

3 years ago

Write an equation for a quadratic function that has x intercepts (-3, 0) and (5, 0)

Blizzard [7]

Answer:

One possible equation is $f(x) = (x + 3)\, (x - 5)$ , which is equivalent to $f(x) = x^{2} - 2\, x - 15$ .

Step-by-step explanation:

The factor theorem states that if $x = x_{0}$ (where $x_{0}$ is a constant) is a root of a function, $(x - x_{0})$ would be a factor of that function.

The question states that $(-3,\, 0)$ and $(5,\, 0)$ are $x$ -intercepts of this function. In other words, $x = -3$ and $x = 5$ would both set the value of this quadratic function to $0$ . Thus, $x = -3\!$ and $x = 5\!$ would be two roots of this function.

By the factor theorem, $(x - (-3))$ and $(x - 5)$ would be two factors of this function.

Because the function in this question is quadratic, $(x - (-3))$ and $(x - 5)$ would be the only two factors of this function. In other words, for some constant $a$ ( $a \ne 0$ ):

$f(x) = a\, (x - (-3))\, (x - 5)$ .

Simplify to obtain:

$f(x) = a\, (x + 3)\, (x - 5)$ .

Expand this expression to obtain:

$f(x) = a\, (x^{2} - 2\, x - 15)$ .

(Quadratic functions are polynomials of degree two. If this function has any factor other than $(x - (-3))$ and $(x - 5)$ , expanding the expression would give a polynomial of degree at least three- not quadratic.)

Every non-zero value of $a$ corresponds to a distinct quadratic function with $x$ -intercepts $(-3,\, 0)$ and $(5,\, 0)$ . For example, with $a = 1$ :

$f(x) = (x + 3)\, (x - 5)$ , or equivalently,

$f(x) = x^{2} - 2\, x - 15$ .

6 0

2 years ago

Solve the following rational equation plz help!!

Yuri [45]

Answer:

x = $\frac{9}{4}$

Step-by-step explanation:

Given

$\frac{4x}{x+1}$ - $\frac{5}{x}$ = $\frac{4}{x^2+x}$ ← factor denominator

$\frac{4x}{x+1}$ - $\frac{5}{x}$ = $\frac{4}{x(x+1)}$

[ x ≠ 0, x ≠ - 1 as these would make the terms undefined ]

Multiply through by x(x + 1)

4x² - 5(x + 1) = 4

4x² - 5x - 4 = 4 ( subtract 4 from both sides )

4x² - 5x - 9 = 0 ← in standard form

(x + 1)(4x - 9) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

4x - 9 = 0 ⇒ 4x = 9 ⇒ x = $\frac{9}{4}$

However, x ≠ - 1 for reason given above, then

solution is x = $\frac{9}{4}$

4 0

3 years ago

Given that 5 x − 3 y = 32 Find y when x = 4

ollegr [7]

Answer:

Solution,

X=4

Now,

 $5x - 3y = 32 \\ or \: 5 \times x - 3y = 32 \\ or \: 5 \times 4 - 3y = 32 \\ or \: 20 - 3y = 32 \\ or \: - 3y = 32 - 20 \\ or \: - 3y = 12 \\ or \: y = - \frac{12}{ 3} \\ y = - 4$ 

Hope this helps...

Good luck on your assignment..

4 0

3 years ago

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