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mr_godi [17]
3 years ago
12

What is the answer ?

Mathematics
2 answers:
Softa [21]3 years ago
8 0

Answer:

353

Step-by-step explanation:

355-42=x-40

I just need to subtract 2 from 355 to get x because I subtracted 2 from 42 to get 40.

355-2=353=x

salantis [7]3 years ago
3 0
The answer is 353 :D
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Just divide then subtract

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Please answer I will be giving out brainliest and 2<br>7 points.​
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Delaney bought a crate for her puppy when it was 3 months old. The crate is in the shape of a rectangular prism. Since the puppy
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Answer:

The volume of the new crate is exactly 174.4% of the old crate.

Step-by-step explanation:

Volume of a rectangular prism:

The volume of a rectangular prism of dimensions x, y and z is given by:

V = xyz

She decided that the dimensions of the new crate needs to be increased by 40% of the original length.

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V = 1.4x(1.4y)(1.4z) = (1.4)^3(xyz) = 2.744(xyz)

Percentage:

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7 0
3 years ago
The length of a rectangular flower bed is 2ft longer than the width. If the area is 6ft, then what are the exact length and widt
Marizza181 [45]

Answer:

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

Step-by-step explanation:

Let's assume width of rectangle is w ft

The length of a rectangular flower bed is 2ft longer than the width

so,

length =w+2

L=w+2

now, we can find area

A=L\times W

now, we can plug it

A=(w+2)\times w

A=w^2+2w

we are given area =6

so, we can set it equal

and then we can solve for w

w^2+2w=6

w^2+2w-6=0

we can use quadratic formula

ax^2+bx+c=0

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

now, we can compare and find a,b and c

a=1 , b=2 , c=-6

w=\frac{-2\pm \sqrt{2^2-4\cdot \:1\left(-6\right)}}{2\cdot \:1}

w=-1+\sqrt{7},\:w=-1-\sqrt{7}

we know that dimension can never be negative

so, we will only consider positive value

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

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