The path of a ball thrown can be modeled by the equation f(x)=−16x^2+45x+6, where x is the horizontal distance. Use a transforma
1 answer:
Answer:
g(x) = -4x^2 +(45/2)x +6
Step-by-step explanation:
A function is scaled horizontally by replacing x with x/k, where k is the expansion factor. Here, we want to expand the graph horizontally by a factor of 2, so the new function will be f(x/2).
g(x) = f(x/2) = -16(x/2)^2 +45(x/2) +6
g(x) = -4x^2 +(45/2)x +6
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