The equation is. -0.5p-2=p how do I solve this?? And show my work
1 answer:
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x² - 5x - 24 = 0
First, we have to solve the quadratic equation and find the two values of x that fit the equation.
There are two values of x that fit:
x₁ = (5+11)/2 = 16/2 = 8
x₂ = (5-11)/2 = -6/2 = -3
Now I can restate the original equation in terms of a product of factors, with this product being equal to zero:
(x - x₁) * (x - x₂) = 0
ANSWER (x-8) * (x+3) = 0
Now I can solve each factor by setting each one equal to zero and solving the resulting linear equations:
x - 8 = 0 or x + 3 = 0
x = 8 or x = -3
We can check that these two values are the solution to the original quadratic equation.
x² - 5x - 24 = 0
First value
8² -5*8 -24 = 0
64 - 40 -24 = 0
0 = 0 ¡Checked!
Second value
(-3)² -5(-3) -24 = 0
9 + 15 -24 = 0
0 = 0 ¡Checked!
Hope this helps!
Answer:
From five given points it is find that points (1 , 1) and (4 , -1) will apply
Step-by-step explanation:
According to question,
Slop of line (m) =
And y-intercept is ( 0, )
So from above slope and points, the equation of line can be written as
y = mx + c
i.e =
x + c
=
(0) + c
= 0 + c
Or, c =
A) With points ( 5, )
At x = 5, y = (5) +
or, y = +
so, y =
Hence this points do not apply
B) With points ( 1 , 1 )
At x = 1, y = (1) +
or, y =
So, y =
y = 1
Hence this points will apply
C) With points ( 4 , -1 )
At x = 4 , y = (4) +
y =
y =
So, y= -1
Hence this points will apply
D) With points (-3 ,7)
At x = - 3, y = (-3) +
y =
Hence this point will not apply
E) with points (0 , 0)
At x 0, y = (0) +
Or, y = 0 +
y =
Hence this point will not apply
∴ From above five given points it is find that points (1 , 1) and (4 , -1) apply
Answer