Answer:
Time to land on 11ft is 4.25 seconds
Step-by-step explanation:
Given

Required
Solve for t when height is 11ft
This implies that 
So: substitute 11 for y in 

Collect Like Terms


Express both sides as squares


Take square roots of both sides (ignore negative)

Solve for t


Hence, time to land on 11ft is 4.25 seconds
21. 1/7 3/8 1/2
23. 3 5/8 3 3/8 3 1/2
25. 1/6 3/4 2/3
First we need to do 12 ÷ 4 to see how many times that goes in. You get 3. Then you do
Hello,
y=-2x
Slope of the line perpendicular : ?*(-2)=-1==>?=1/2
The equation is:
y-2=1/2(x-2)
==>y=x/2-1+2
==>y=x/2+1