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3 years ago

Given that and , determine which lines are parallel

1 answer:

7 0

What lines and here is how parallel looks

_________
_________

these lines r parallel
and parallel lines r lines that go on forever but NEVER touch

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Question 17 i need help answer is -16 but don’t know how

Mila [183]

Answer:

-16

Step-by-step explanation:

-k² -(3k-5n)+4n k=-1 , n= -2

= -(-1)² - ( 3(-1) -5(-2) )+4(-2)

= -1-(-3+10)-8

= -1-(7)-8

= -1-7-8

= -16

4 0

3 years ago

Explain why each of the following integrals is improper. (a) 4 x x − 3 dx 3 Since the integral has an infinite interval of integ

erma4kov [3.2K]

Answer:

Since the integral has an infinite discontinuity, it is a Type 2 improper integral

Since the integral has an infinite interval of integration, it is a Type 1 improper integral

Since the integral has an infinite discontinuity, it is a Type 2 improper integral

Step-by-step explanation:

Considering a

$\int\limits^4_3 {\frac{x}{x- 3} } \, dx$

Looking at this we that at x = 3 this integral will be infinitely discontinuous

Considering b

$\int\limits^{\infty}_0 {\frac{1}{1 + x^3} } \, dx$

Looking at this integral we see that the interval is between $0 \ and \ \infty$ which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral

Considering c

$\int\limits^{\infty}_{- \infty} {x^2 e^{-x^2}} \, dx$

Looking at this integral we see that the interval is between $-\infty \ and \ \infty$ which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral

Considering d

$\int\limits^{\frac{\pi}{4} }_0 {cot (x)} \, dx$

Looking at the integral we see that at x = 0 cot (0) will be infinity hence the integral has an infinite discontinuity , so it is a Type 2 improper integral

7 0

3 years ago

-4(2x - 3)<br>please help fast !!!!

Ber [7]

Answer:

-8x+12

You have to distrivute the -4 into the parenthesis so to solve the problem you multiply -4*(-2x)+=-8x and -2*(-3)=6

7 0

3 years ago

Read 2 more answers

What is the equation of the third rocket?

ivann1987 [24]