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2 years ago

Six mini cakes and 10 cookies cost

Mathematics

2 answers:

Rus_ich [418]2 years ago

8 0

A cookie costs 7 dollars and a mini cake costs 5 dollars

lana [24]2 years ago

6 0

Answer:

The cost of one mine cake is $5
The cost of one cookie is $7

Step-by-step explanation:

6m + 10c = $100
=> 6m + 5c = $65

=> 5c = 35
=> c = 7
=> 6m + 10(7) = $100
=> 6m + 70 = 100
=> 6m = 100 - 70
=> 6m = 30
=> m = 5

Conclusion:

Therefore:

The cost of one mine cake is $5
The cost of one cookie is $7

Hoped this helped.

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borishaifa [10]

Answer:

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Step-by-step explanation:

The decimal moves over one place each time

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Step-by-step explanation:

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This should help you

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3 years ago

Can anyone please help me in this

Alik [6]

These problems are called systems of equations. Basically you have two linear equations and you need to find the values for x and y. In other words, all these equation are lines and our answer will be the exact point that the pair of lines intersect. For example, if we get x=1 and y=2 the lines will intersect at point (1,2). Now that you have some background knowledge here comes the tricks and tactics kid.

We know that we can solve one variable equation easily. For example...

x+1=2

x=1 obviously

Cause we have two variables x and y it is not possible to find a solution. For example, in the equation x+y=10, x=1 when y=9 and x=2 when y=8. There is not correct answer.

So what can we do? We have to make a two variable equation into a one variable equation.

There are two ways to do this: substitution and elimination. I will create a sample problem and then solve it using both methods.

x+y=2

2y-y=1

-3x-5y=-7 -----> -12x-20y=-28

-4x-3y=-2 ------> -12x-9y=-6

-12x-20y=-28

-(-12x-9y=-6)

---------------------

-11y=-22

y=2

-3x-5(2)=-7

-3x=3

x=-1

4) 8x+4y=12 ---> 24x+12y=36

7x+3y=10 ---> 28x+12y=40

28x+12y=40

-(24x+12y=36)

---------------------

4x=4

x=1

8(1)+4y=12

4y=4

y=1

5) 4x+3y=-7

-2x-5y=7 ----> -4x-10y=14

4x+3y=-7

+(-4x-10y=14)

-------------------

-7y=7

y=-1

4x+3(-1)=-7

4x=-4

x=-1

6) 8x-3y=-9 ---> 32x-12y=-36

5x+4y=12 ---> 15x+12y=36

32x-12y=-36

+(15x+12y=36)

--------------------

47x=0

x=0

8(0)-3y=-9

-3y=-9

y=3

7)-3x+5y=-2

2x-2y=1 ---> x-y=1/2 ----> x=y+1/2

-3(y+1/2)+5y=-2

-3y-1.5+5y=-2

2y=-0.5

y=0.25

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2x=1.5

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4 0

3 years ago

Write an absolute value inequality that

fiasKO [112]

Answer:

All real numbers greater than or equal to -1 and less than or equal to 2

Step-by-step explanation:

Let

A_1 ------> the area of rectangle

A_2 ----> the area of triangle

we know that

$\left|A_1-A_2\right|\le 6$

Find out the area of rectangle

$A_1=4(x+2)=(4x+8)\ units^2$

Find out the area of triangle

$A_2=(1/2)(4)(5)=10\ units^2$

substitute

$\left|(4x+8)-10\right|\le 6$

Simplify

$\left|4x-2\right|\le 6$

First case (positive value)

$+(4x-2) \leq 6$

$4x \leq 6+2$

$4x \leq 8$

$x \leq 2$

Second case (negative value)

$-(4x-2) \leq 6$

Multiply by -1 both sides

$(4x-2) \geq -6$

$(4x \geq -6+2$

$4x \geq -4$

$x \geq -1$

therefore

The solution for x is the interval -----> [-1,2]

All real numbers greater than or equal to -1 and less than or equal to 2

8 0

3 years ago