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3 years ago

Lake Michigan is the fifth largest lake

Mathematics

2 answers:

nikklg [1K]3 years ago

6 0

Yes with a 58,016 Square Kilometers

velikii [3]3 years ago

3 0

This is true, Lake Michigan is the fifth largest lake in the world. Hope this Helps:)))

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nexus9112 [7]

I d k what this is but okay

3 0

2 years ago

A kayaker travels x miles per hour downstream for 4 hours. On the 6-hour return trip, the kayaker travels 2 mile per hour slower

Stolb23 [73]

time * rate = distance

Downstream 4 * x = 4(x)

Upstream 6 * x - 2 = 6(x - 2)

distance downstream = distance upstream:

4(x) = 6(x - 2)

4x = 6x - 12

-2x = -12

x = 6

Distance Upstream: 4x = 4(6) = 24

Distance Upstream: 6(x - 2) = 6(6 - 2) = 6(4) = 24

Total distance traveled is Upstream + Downstream = 24 + 24 = 48

Answer: 48 miles

5 0

3 years ago

What happened to the tutor option :(

ElenaW [278]

Answer: wym

Step-by-step explanation:

6 0

3 years ago

What is the measure of arc CD?

CaHeK987 [17]

Option C:

The measure of arc CD is 40°.

Solution:

Given data:

m∠X = 11° and m(arc AB) = 18°

To find the measure of arc CD:

We know that,

Angle formed by two intersecting secants outside the circle is equal to half of the difference between the intercepted arcs.

$$m \angle X =\frac{1}{2}({arc \ CD}-{arc} \ AB)$

$$ 11^\circ =\frac{1}{2}({arc} \ CD-{18^\circ})$

Multiply by 2 on both sides.

22° = arc CD - 18°

Add 18° from both sides.

40° = arc CD

Switch the sides.

arc CD = 40°

Hence the measure of arc CD is 40°.

Option B is the correct answer.

7 0

3 years ago

The equation of a circle is given below.

BARSIC [14]

Given:

The equation of the circle is $x^2+(y+4)^2=64$

We need to determine the center and radius of the circle.

Center:

The general form of the equation of the circle is $(x-h)^2+(y-k)^2=r^2$

where (h,k) is the center of the circle and r is the radius.

Let us compare the general form of the equation of the circle with the given equation $x^2+(y+4)^2=64$ to determine the center.

The given equation can be written as,

$(x-0)^2+(y+4)^2=64$

Comparing the two equations, we get;

(h,k) = (0,-4)

Therefore, the center of the circle is (0,-4)

Radius:

Let us compare the general form of the equation of the circle with the given equation $x^2+(y+4)^2=64$ to determine the radius.

Hence, the given equation can be written as,

$x^2+(y+4)^2=8^2$

Comparing the two equation, we get;

$r^2=8^2$

$r=8$

Thus, the radius of the circle is 8

3 0

3 years ago