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mariarad [96]
2 years ago
9

Let g(x) = sqrt2x/ln(x) find g'(x)

Mathematics
1 answer:
nikklg [1K]2 years ago
5 0

Answer:

Step-by-step explanation:

Download pdf
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) Using the chart, approximate the limit of the function f(x) = sin x/ x as x approaches zero. Note the numbers are in radians:
Rashid [163]

Answer:

1

Step-by-step explanation:

We are given that

f(x)=\frac{sinx}{x}

Numbers are in radians

Substitute x=-1

f(-1)=\frac{sin(-1)}{-1}=0.84

Substitute x=-0.25

f(-0.25)=\frac{Sin(-0.25)}{-0.25}=0.989

Substitute x=-0.01

f(-0.01)=\frac{sin(-0.01)}{-0.01}=0.999

Substitute x=-0.005

f(-0.005)=\frac{sin(-0.005)}{-0.005}=0.999

Substitute x=0.005

f(0.005)=\frac{sin(0.005)}{0.005}=0.999

Substitute x=0.01

f(0.01)=\frac{sin(0.01)}{0.01}=0.999

Substitute x=0.25

f(0.25)=\frac{sin(0.25)}{0.25}=0.989

Substitute x=1

f(1)=\frac{sin(1)}{1}=0.84

Therefore, \lim_{x\rightarrow 0}\frac{sinx}{x}=1

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4 years ago
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