The dimensions of the square base after cutting the corners will be (40-2x). The depth of the box will be x, so its volume is given by
V = x(40-2x)²
You can differentiate this to get
V' = 12x² -320x -1600
Setting this to zero and factoring gives
(3x-20)(x-20) = 0
The appropriate choice of solutions is
x = 20/3 = 6 2/3
The
dimensions of the box of maximum volume are
26 2/3 in square by 6 2/3 in deepThe
maximum volume is
(80/3 in)²(20/3 in) =
4740 20/27 in³
The first thing I did was follow all the instructions using MS Excel as a tools. First I plot the two points (3,2) and (7,12). Then, I scaled the x-axis from 0 to 9 with increments of 1, and 0 to 18 for the y-axis with increments of 2. Finally, I extended the line by connecting the two dots and extending both sides. The result is shown in the picture.
So, from the scale of the axes alone, the domain of the function is the coverage of all its x-values. If the line has coordinates on that x-value, it is part of the domain. Basing on the picture the domain is 2.2≤x≤9. So, the lower limit must not be lower than 2, and the upper limit must not be greater than 9. Among the choices, the accepted values that are still part of the domain is <span>
3 ≤ x ≤ 7.</span>
Answer:
w = 2
Step-by-step explanation:
Answer:
By 2 or 7
Step-by-step explanation:
7*2=14