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ss7ja [257]
3 years ago
11

find the length of each isosceles right triangle when the hypotenuse is of the given measure given 8cm

Mathematics
1 answer:
Wewaii [24]3 years ago
4 0

It is given that the triangle is isosceles right triangle . And in an isosceles right triangle the legs are equal . Let each leg be of x units. Now we use pythagorean identity, which is

a^2 +b ^2=c^2

x^2 +x^2 = 8^2

2x^2 = 64

x^2 = 32

x = 4 \sqrt 2

So the length of each leg is 4 \sqrt 2 .

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The line thru (-3,0) and (-6,5) has this slope:

          5-0            5
m = ----------- = ------- = - 5/3
         -6-(-3)       -3

The y-intercept of the desired line is simply (0,0), and so b = 0 and the equation of this line is

y = (-5/3)x
8 0
3 years ago
A number q divided by 5 is 8
oee [108]

Answer:

q = 40

Step-by-step explanation:

\frac{q}{5} = 8

multiply 5 on boths sides:

\frac{q}{5} x 5 = 8 x 5

q = 40

to check:

\frac{40}{5} = 8

8 0
3 years ago
Read 2 more answers
HELP ME!!!!!!!!!!!!!!!!!!!plz HURRYYYYYY
grandymaker [24]

Answer:

i would say the answer is  (b) 40

Step-by-step explanation:

7 0
3 years ago
Can someone help me on this one please
Paul [167]

Answer:

x=-2

Step-by-step explanation

x+74+37+x+73=180

184+2x=180

-184        -184

2x=-4

x=-2

8 0
3 years ago
90 points!!
Svetllana [295]

Answer:

1) 2w + 2(3w) \leq 112

2) 850w > 300w + 7500

3) The greatest age that Sue could be is 7.

4) The smaller of the two integers is 92.

5) Don needs to earn at least 244 points in the fourth game.

Step-by-step explanation:

1) An rectangle has 2 dimensions: width(w) and length(l)

The perimeter P is:

P = 2w + 2l

The problem states that the length of a rectangle is three times its width. So l = 3w and:

P = 2w + 2(3w)

The perimeter of the rectangle is at most 112 cm. It means that the perimeter can be 112, so the equal sign enters the inequality. So

2w + 2(3w) \leq 112

2)

The problem states that he earns $850 per week in sales. His earnings is modeled by the following equation:

E = 850*w, in which w is the number of weeks.

The problem also states that he spent $7500 to obtain his merchandise, and it costs him $300 per week for general expenses. So his expenses can be modeled by the following equation

C = 300*w + 7500, in which w is also the number of weeks.

He will make a profit when his earnings are bigger than his expenses, so: When they are equal, there is no profit, so the equal sign does not enter the inequality.

E > C

850w > 300w + 7500

3)

I am going to call Jenny's age x and Sue's age y.

The problem states that Jenny is eight years older than twice her cousin Sue’s age. So

x = 8 + 2y.

The sum of their ages is less than 32, so:

x + y < 32

8 + 2y + y < 32

3y < 24

y < \frac{24}{3}

y < 8

Sue's age has to be less than 8, so the greatest age that Sue could be is 7.

4)

The sum of two consecutive integers is at least 185.

There are two integers with sum of 185, so:

x + y = 185

They are consecutive so:

x = y + 1

Replacing in the sum equation:

y + 1 + y = 185

2y = 184

y = \frac{184}{2}

y = 92

The smaller of the two integers is 92.

5)

The average is the sum of all the scores divided by the number of games. So:

225 = \frac{192 + 214 + 250 + x}{4}

656 + x = 900

x = 900 - 656

x = 244

Don needs to earn at least 244 points in the fourth game.

8 0
3 years ago
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