Using the information given, it is found that the class width for this frequency distribution table is of 1.
In this problem, these following classes are given:
0 – 1 14
2 – 3 1
4 – 5 8
6 – 7 12
8 – 9 12
The classes not given, which are 1 - 2, 3 - 4 and 5 - 6, have values of 0.
The <u>difference between the bounds of the classes is of 1</u>, thus, the class width is of 1.
A similar problem is given at brainly.com/question/24701109
Answer:
The answer to your question is below
Step-by-step explanation:
I numbered the squares, see the picture below
Angle 3 and the angle given are vertical angles so they measure the same
angle 3 = 137°
The sum of the angles 1, 2, 3 and 137 equals 360°, so
angle 1 + 137 + angle 3 + 137 = 360
and angle 1 and 3 are vertical angles so angle 1 = angle 3
2angle 1 = 360 - 137 -137
2 angle 1 = 86
angle 1 = 86 /2
angle 1 = 43°
angle 2 = 43°
The angle given and the angle 5 are corresponding angles, they measure the same
angle 5 = 137°
Angle 5 and 6 are vertical angles, they measure the same
angle 6 = 137°
Angle 2 and angle 7 are corresponding angles, they measure the same
angle 7 = 43°
Angle 3 and angle 6 are corresponding angles
angle 6 = 137°
Angle 4 and 7 are vertical angle, so they measure the same
angle 4 = 43°
Answer:
85% off $51 is $43.35 which equals to $7.65
Amanda paid only $7.65 for the 85% off the original price.
Step-by-step explanation:
V=4/3 x pi r cubed thats the ewuation for the volume of a sphere