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4 years ago

5

Write as a power of 8

id="TexFormula1" title="8 {}^{30} \div 8 {}^{6} " alt="8 {}^{30} \div 8 {}^{6} " align="absmiddle" class="latex-formula">

1 answer:

ycow [4]4 years ago

6 0

It equals
${8}^{24}$

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It is a 2/13 probability

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3 years ago

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Someone please help explain this

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3 years ago

Out of 25 children, 10 children like science subject and 15 children like English. 7 children like both the subjects.

sesenic [268]

<h2>Question:</h2>

Out of 25 children, 10 children like science subject and 15 children like English. 7 children like both the subjects. How many students don't like any subject?

<h2>Answer:</h2>

7 children.

<h2>Step-by-step explanation:</h2>

This can be solved by drawing a Venn diagram. The diagram is attached to this response.

<em>Given</em>:

Total number of children = 25

Number that like both subjects = 7

Number that like science = 10

Number that like English = 15

<em>Unknown</em>

Let the number of children that like science alone be s

Let the number of children that like English alone be e

Let the number of children that do not like any subject be x

s = Number that like science - number the like both subjects.

s = 10 - 7

s = 3

e = Number that like English - number the like both subjects.

e = 15 - 7

e = 8

Total number of children = Number that like science alone + Number that like English alone + Number that like both subjects + Number that do not like any subject.

<em>This implies that;</em>

25 = 3 + 8 + 7 + x

<em>Solving for </em><em>x</em><em> gives;</em>

25 = 18 + x

x = 25 - 18

x = 7

Therefore, 7 children do not like any subject.

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3 years ago

Help plz I really don’t know what to do

castortr0y [4]

Answer:

If they have the same variable you add or subtract them.

Step-by-step explanation:

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3 years ago

Extended Problems, Extraneous Solutions

diamong [38]

Answer:

1a. 2 is the solution

1b. -3 is because square root of 1 doesn't equal -1.

1c.-3

Step-by-step explanation:

1.

$(x + 2 = \sqrt{3x + 10}$

Square both sides

$(x + 2) {}^{2} = 3x + 10$

Remeber perfect square Rule

$(x + y) {}^{2} = {x}^{2} + 2xy + {y}^{2}$

So now we got

$x {}^{2} + 4x + 4 = 3x + 10$

${x}^{2} + x + 4 = 10$

${x}^{2} + x - 6 = 0$

Factor into binomial.

$(x + 3)(x - 2) = 0$

So our solution is 3 or 2. However, let's check our work.

$- 3 + 2 = \sqrt{3( - 3) + 10}$

$- 1 = \sqrt{1}$

However square root of 1 is 1. It could be 1 but in Math, <em>We</em><em> </em><em>only</em><em> </em><em>take</em><em> </em><em>the</em><em> </em><em>principal</em><em> </em><em>square</em><em> </em><em>root</em><em> </em><em>which</em><em> </em><em>is</em><em> </em><em> </em><em>positive</em><em> </em><em>always</em><em>.</em><em> </em><em>So</em><em> </em><em>-3</em><em> </em><em>isn't</em><em> </em><em>a</em><em> </em><em>solution</em><em>.</em>

<em>So</em><em> </em><em>let</em><em> </em><em>try</em><em> </em><em>2</em><em>.</em>

<em> $2 + 2 = \sqrt{3(2) + 10} = 4 = \sqrt{16} = 4 = 4$ </em>

<em>So</em><em> </em><em>this</em><em> </em><em>is</em><em> </em><em>indeed</em><em> </em><em>the</em><em> </em><em>solution</em><em>.</em>

<em>Make</em><em> </em><em>up</em><em> </em><em>equation</em><em> </em><em>for</em><em> </em><em>2</em><em> </em><em>and</em><em> </em><em>3</em><em>.</em><em> </em><em>Ask</em><em> </em><em>me</em><em> </em><em>if</em><em> </em><em>you</em><em> </em><em>need</em><em> </em><em>help</em><em>.</em>

5 0

3 years ago