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charle [14.2K]
3 years ago
5

When Pheobe asked her friends about their Thanksgiving, 35% of her 60 friends said they had pumpkin pie for dessert. How many fr

iends had pumpkin pie for dessert?
im bad at algebra srry
Mathematics
2 answers:
evablogger [386]3 years ago
5 0
21.

x/60 = 35/100. Multiply 35 and 60 then divide by 100. x = 21
nataly862011 [7]3 years ago
4 0

Answer:

21

Step-by-step explanation:

I dunno, I used a calculator B)

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alukav5142 [94]

Answer:9.3 repeated

Step-by-step explanation: Because ppl r judgy. They judge books by the cover.

6 0
3 years ago
What is the answer need help
abruzzese [7]

Answer:

2

Step-by-step explanation:

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3 0
3 years ago
4.5 lbs of carnitas / 15 sweet rolls
Rom4ik [11]
What is the question exactly?
3 0
3 years ago
the marks in an examination for a Physics paper have normal distribution with mean μ and variance σ2 . 10% of the students obtai
Blababa [14]

Let X be the random variable for the number of marks a given student receives on the exam.

10% of students obtain more than 75 marks, so

P(X>75)=P\left(\dfrac{X-\mu}\sigma>\dfrac{75-\mu}\sigma\right)=P(Z>z_1)=0.10

where Z follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

P(Z>z_1)=1-F_Z(z_1)=0.10\implies z_1=F_Z^{-1}(0.90)

where F_Z(z)=P(Z\le z) denotes the CDF of Z, and F_Z^{-1} denotes the inverse CDF. We have

z_1=F_Z^{-1}(0.90)\approx1.2816

Similarly, because 20% of students obtain less than 40 marks, we have

P(X

so that

P(Z

Then \mu,\sigma are such that

\dfrac{75-\mu}\sigma\approx1.2816\implies75\approx\mu+1.2816\sigma

\dfrac{40-\mu}\sigma\approx-0.8416\implies40\approx\mu-0.8416\sigma

and we find

\mu\approx53.8739,\sigma\approx16.4848

3 0
4 years ago
Hello please help i’ll give brainliest
crimeas [40]

Answer:

the 2nd one

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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