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2 years ago

Select the two values of x that are roots of this equation 2x^2-11x+15=0

1 answer:

3 0

X=5/2 and 3. Factor the equation find numbers that will sum up too -11 involving the coefficient of 2, and that multiply into 15. 2x too the power of 2 -11x +15=0 (2x-5)(x-3) =0

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10 quarters 17 dimes 40 nickels 15 pennies answer

Oliga [24]

If the given quantities are 10 quarters 17 dimes 40 nickels 15 pennies then the total money would be 6.35 dollars.

<h3>What is the fundamental principle of multiplication?</h3>

If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.

Quarters are worth .25 of a dollar

10 x .25 = 2.5

Dimes are worth .10 of a dollar

17 x .10 = 1.7

Nickels are worth .05 of a dollar

40 x .05 = 2

Pennies are worth .01 of a dollar

15 x .01 = 0.15

Add this together

2.5 + 1.7 + 2 + 0.15

= 6.35

Learn more about multiplication;

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4 0

1 year ago

Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )

Zina [86]

Answer:

$\purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$

Step-by-step explanation:

$\cos( \alpha ) = \frac{ \sqrt{6} }{6} = \frac{1}{ \sqrt{6} } \\ \\ \therefore \: \sin( \alpha ) = \sqrt{1 - { \cos}^{2} ( \alpha ) } \\ \\ = \sqrt{1 - \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} } \\ \\ = \sqrt{1 - {\frac{1}{ {6} }}} \\ \\ = \sqrt{ {\frac{6 - 1}{ {6} }}} \\ \\ \red{\sin( \alpha ) = \sqrt{ { \frac{5}{ {6} }}} } \\ \\ \tan( \alpha ) = \frac{\sin( \alpha ) }{\cos( \alpha ) } = \sqrt{5} \\ \\ \sin( \beta ) = \frac{ \sqrt{2} }{4} \\ \\ \implies \: \cos( \beta ) = \sqrt{ \frac{7}{8} } \\ \\ \tan( \beta ) = \frac{\sin( \beta ) }{\cos( \beta ) } = \frac{1}{ \sqrt{7} } \\ \\ \tan( \alpha - \beta ) = \frac{ \tan \alpha - \tan \beta }{1 + \tan \alpha . \tan \beta} \\ \\ = \frac{ \sqrt{5} - \frac{1}{ \sqrt{7} } }{1 + \sqrt{5} . \frac{1}{ \sqrt{7} } } \\ \\ = \frac{ \sqrt{35} - 1 }{ \sqrt{7} + \sqrt{5} } \\ \\ \purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$

8 0

2 years ago

Let f(x)=18/1+3^e-0.1x What is the point of maximum growth rate for the logistic function f(x)? Show all work. Round your answer

xz_007 [3.2K]

Answer:

(0, 4.5)

Step-by-step explanation:

*The equation can be put into Desmos, to find the point, but the work to prove it is here*

f(x)=c/1+Ae^-Bx

Y=C

C=18 A=3 -B=-0.1

*Replace x with 0 in the equation, so you know 0 is the x value, and it leads you to the y value*

f(0)=18/1+3e^-o.1(0)

= 18/1+3e^0

=18/1+3(1)

=18/1+3

=18/4

=4.5

x=0 y=4.5

Maximum growth rate = (x,y) --> (0, 4.5)

Hope this helps:))!!

5 0

2 years ago

The value of y directly varies with the value of x. If y equals 21when x is 14, what is the value of y when x = 20?

Karo-lina-s [1.5K]

Answer:

21×20÷14

=3×20÷2

=3×10

x=30

8 0

2 years ago

Q11.

Kamila [148]

Answer:

Step-by-step explanation:

The area of a trapezium is given as;

Area = $\frac{1}{2}$ (a + b)h

where: a is the length of the upper side, b is the length of its base and h is its height.

This implies that; a = x - 4, b = x + 5, h = 2x and area = 351

Thus,

351 = $\frac{1}{2}$ ((x - 4) + (x + 50)) 2x

= (x - 4 + x + 5) x

531 = (2x + 1) x

= 2 $x^{2}$ + x

So that;

2 $x^{2}$ + x - 531 = 0

This gives a quadratic equation.

5 0

2 years ago