The volume of HCl gas required to prepare the solution is 101.54 L
<h3>How to determine the mole of HCl </h3>
- Volume of solution = 1.25 L
- Molarity = 3.20 M
- Mole of HCl =?
Mole = Molarity x Volume
Mole of HCl = 3.2 × 1.25
Mole of HCl = 4 moles
<h3>How to determine the volume of HCl </h3>
- Number of mole (n) = 4 moles
- Temperature (T) = 30 °C = 30 + 273 = 303 K
- Pressure (P) = 745 torr = 745 / 760 = 0.98 atm
- Gas constant (R) = 0.0821 atm.L/Kmol
Using the ideal gas equation, the volume of the HCl gas can be obtained as follow:
PV = nRT
Divide both side by P
V = nRT / P
V = (4 × 0.0821 × 303) / 0.98
V = 101.54 L
Learn more about ideal gas equation:
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Answer:
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Explanation:
The price of the new vehicle without tax is $5,876.06
The tension on each segment of the clothesline is : 110 N
<u>Given data : </u>
mass of object = 100 n = 10 kg
Horizontal distance of clothesline = 4 m
middle of clothesline sag s by : 1m
<h3 /><h3>Determine the tension on each segment of clothesline</h3>
<u>First step</u> : calculate the horizontal angle made by the sagging
β = arctan ( 1 m / 2m ) ----- ( 1 )
= arctan ( 0.5 )
≈ 26.57°
Note : Tension in th y axis ( Ty ) = Tsinβ
Therefore :
Tension on each segment can be calculated using the formula below
2Tsinβ - mg = 0
solve for T
T = mg / 2sinβ
= ( 10 * 9.8 ) / 2 * sin 26.57°
= 98 / 0.89
= 110 N
Hence we can conclude that the tension on each segment of the clothesline is : 110 N
Learn more about Tension calculations : brainly.com/question/24994188
