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love history [14]
2 years ago
10

Using scalar multiplication, find 5u if u= <2, 4>.

Mathematics
1 answer:
kicyunya [14]2 years ago
7 0

Using scalar multiplication, it is found that 5u = <10,20>.

<h3>What is scalar multiplication?</h3>
  • It is when a vector is multiplied by a constant, and it means that each term of the vector is multiplied by the constant.

In this problem, the vector is:

u = <2,4>

Since each term is multiplied by 5:

5u = <5 x 2, 5 x 4> = <10,20>.

To learn more about scalar multiplication, you can take a look at brainly.com/question/1821869

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Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.

A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'

B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)

C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
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.. y = n*x/(m+p)

D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n

_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.

The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
7 0
3 years ago
I need help please.........
kogti [31]
This is what I got I hope it can help you

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Anne creates necklaces and rings to sell. It takes her 3 hours to make a necklace and 1 hour to make a ring. If she makes 10 ite
ankoles [38]
Hi! to solve the question, how many necklaces did anne make in 16 hours if she makes 10 items in 2 standard 8-hour work days, we should first check the time she needs to make each item.

3 individual hours to make a necklace, and 1 hour to make a ring. according to the problem, she made 10 items in 16 hours. this problem will most likely be trial and error. let’s try one first guess.

my first guess will be, maybe she will make 6 rings and 4 necklaces. 6 times 1 is 6, which takes 6 hours for the rings. 4 times 3 is equal to 12. 6 + 12 is too high! let’s try again.

what about 6 rings and 2 necklaces? 6 times 1 is 6, so that’s 6 hours. 2 times 3 is 6 hours! 6 plus 6 is 12, which is close, but not quite there!

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so, the answer would be, “Anne made 7 rings and 3 necklaces within 16 hours.” hope this helped!:)
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