Answer:
a. The allele for round seeds is dominant to the allele for wrinkled seeds.
Explanation:
Mendel found that when two pure breeding plants that differ from each other with respect to one genetic trait are crossed, all the progeny express the phenotype of one parent. The phenotype of the other parent is not expressed in the progeny. He concluded that the genetic trait that is expressed in the F1 generation is dominant over the other which is masked in this generation.
A cross between pure breeding plants for round seeds and the wrinkled seeds obtained all the round seeded progeny. This meant that the phenotype "round" was dominant over the phenotype "wrinkled". If the allele "R" gave round phenotype and the allele "r" imparted wrinkled phenotype, the allele "R" was dominant to the "r".
Answer:
Cell cycle checkpoints are checking for malformations in the cell that could be potentially dangerous later down the line.
Explanation:
The enzyme that would be most important for digesting a skinless chicken breast would be a PEPTIDASE.
A skinless chicken breast is a proteinous food and peptidases are enzymes which break down proteins by hydrolysis of the peptide bonds which joined the amino acids of proteins together.
<h2>Answer:</h2>
If the formula for glucose is C6H12O6, Six number of carbon atom will used to produce a glucose.
Equation:
6CO2 + 6H2O + light energy = C6H12O6 + 6O2.
