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WARRIOR [948]
3 years ago
9

Write the equation in standard form y=-x+1

Mathematics
2 answers:
Dahasolnce [82]3 years ago
6 0
X+y=1.
Add x to both sides to get x and y on the same side. Set equal to value.
maks197457 [2]3 years ago
6 0

Answer:

x+y=1

Step-by-step explanation:

The Linear Equation Standard Form is = ax+by=c.

Given y=-x+1, we will use Algebra to convert the equation from slope-intercept  form to standard form:

x+y=-x+x+1

We added x to both sides to cancel out and move the -x.

x+y=1 is the answer.

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Determine the center and radius of the following circle equation: x^2+y^2-8x+6y-75=0 x 2 +y 2 −8x+6y−75=0 Center: \big(( , \big)
Reptile [31]

Answer:

Compare x^2 +y^2-8x-6y=75 with the general circle equation x^2+y^2 -2ax-2by+c=0

-2a =-8 And -2b=-6

a=4 b=3

c=-75

To find the radius use the equation

r^2=a^2+b^2-c

r^2=4^2+ 3^2-(-75)

r^2=25+75=100

r=10(radius is always positive)

Hence the center is (4,3) and radius 10

Step-by-step explanation:

6 0
3 years ago
HELP ME PLEASE IM SO LOST
DiKsa [7]
A=10ft because A is 8ft so round that to the nearest ten your answer is 10ft
6 0
3 years ago
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What is the graph of the equation? y=-2
Marrrta [24]
Your answer would look like this

8 0
3 years ago
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Identify the function that contains the data in the following table: x     -2         0         2         3         5     f(x)  
Veseljchak [2.6K]

Answer:

f(x) = |x - 2| + 1

Step-by-step explanation:

When x = -2, then f(-2) = 5

The first function gives the relation equation as f(x) = |x| + 1

So, f(-2) = |-2| + 1 = 2 + 1 = 3 ≠ 5

{Since the definition of |x| is given by  

|x| = x, when x ≥ 0 and |x| = - x, when x < 0}

Again, the second  function gives the relation equation as f(x) = |x - 2|.

So, f(-2) = |-2 - 2| = |-4| = 4 ≠ 5

Now, the third function gives the relation equation as f(x) = |x - 2| - 1.

So, f(-2) = |-2 - 2| - 1 = |-4| - 1 = 4 - 1 = 3 ≠5

Again, the fourth function gives the relation equation as f(x) = |x - 2| + 1.

Hence, f(-2) = |-2 - 2| + 1 = |-4| + 1 = 4 + 1 = 5  

Therefore, the fourth function f(x) = |x - 2| + 1 contains the given data table.  

For further clarity we can check f(0) = 3, f(2) = 1, f(3) = 2 and f(5) = 4. (Answer)

6 0
4 years ago
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One x-intercept for a parabola is at the point (11,0) use the factor method to find the other x-intercept for the parabola defin
liberstina [14]
From which lesson or from which chapter
5 0
4 years ago
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