Answer: SEE EXPLANATION (en ingles)
Step-by-step explanation:
A binomial is an algebraic expression of the sum or the difference of two terms.
En espanol: Un binomio es una expresión algebraica de la suma o la diferencia de dos términos.
Answer:
12% or 13% rounded
Step-by-step explanation:
.25 of 2.00 is .125 or 12% or 13% rounded
Let x = total games played
16% = 0.16
0.16x = 40. Divide each number by 0.16.
x = 250
Wendy played 250 games

To find the gradient of the tangent, we must first differentiate the function.

The gradient at x = 0 is given by evaluating f'(0).

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.
The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:
Answer:

Step-by-step explanation:
Hello,
let's solve


There are two solutions

And

So we can write

Hope this helps.
Do not hesitate if you need further explanation.
Thank you