What you would do is simply plug in 8 where y is and solve.
5(8)=3478-3c -Times 5 by 8
40=3478-3c -Add 3c to the opposite side of the equal sign
40+3c=3478 -Subtract 40 from the opposite side of the equal sign
3c=3438 -Divide equation by 3
c=1146

Hope this helps! :)

5 0

3 years ago

The height of the tunnel at the center is 54 ft, and the vertical clearance must be 18 ft at a point 8 ft from the center. Find

IrinaVladis [17]

the standard form for a horizontal ellipse is

X^2/a^2 + y^2/b^2 = 1

Substitute 54 for b and and use (8,18) as the

point to find a

x=8

y=18

8^2/a^2 + 18^2/54^2 =1

64/a^2 + 324/2916 = 1

324/2916 reduces to 1/9

64/a^2 + 1/9 = 1

64/a^2= 1-1/9

64/a^2 = 8/9

64*9/8 = a^2

576/8 = 72

A^2 = 72

A = square root(72) = 8.485

So formula

would be x^2/72 + y^2/2916 =1

8 0

3 years ago

5(x-2)-3= 5x-13help me plz​

5(x-2)-3= 5x-13help me plz