4 years ago

Mr. custom is correcting the class's math homework on customary units. which of the following measurements is reasonable

Mathematics

1 answer:

Romashka [77]4 years ago

6 0

D is the most reasonable as the other 3 answers are improbable.

You might be interested in

I need help!!!!!!!! 2c-2.6=1.8

vodka [1.7K]

Answer:

thats right

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

PLEASE HELP 30 POINTS AND BRAINLY

Umnica [9.8K]

Answer:

I think the option B suits the most

Step-by-step explanation:

8 0

3 years ago

Can someone help, no links plz

AfilCa [17]

Answer:

x=19.4

Step-by-step explanation:

a^2+b^2=c^2

x^2+8^2=21^2

x^2+64=441

x^2=377

square root of 377 is 19.41648784

rounded would be 19.4

5 0

3 years ago

Read 2 more answers

when a number is added to of itself, the result is 24. the equation that models this problem is n n = 24. what is the value n?

Alex777 [14]

To get the value of n in the problem above, divide the sum by the number of n's added together. From the given, n + n = 24, there are only two n's added together. Hence, divided 24 by 2. The answer to this item is 12.

3 0

3 years ago

What is the perimeter of a triangle with vertices located at (1,4), (2,7), and (0.5), rounded to the nearest hundreth?

erik [133]

$\boxed {\text {Length = }\sqrt{(X_2-X_1)^2 + (Y_2-Y_1)^2}}$

The three lengths are:

$\text {Length 1 = }\sqrt{(2-1)^2 +(7-4)^2} = \sqrt{10}$

$\text {Length 2 = }\sqrt{(2-0)^2 +(7-5)^2} = \sqrt{8}$

$\text {Length 3 = }\sqrt{(1-0)^2 +(4-5)^2} = \sqrt{2}$

$\text{Perimeter = } \sqrt{10} + \sqrt{8} + \sqrt{2} = 7.40 \text { (nearest hundredth)}$

Answer: 7.40 units

4 0

4 years ago