Question

Solve for x using common denominators.%2B2%29%7D" id="TexFormula1" title="\frac{3}{4(x+2)}=\frac{x}{(x+2)}" alt="\frac{3}{4(x+2)}=\frac{x}{(x+2)}" align="absmiddle" class="latex-formula">
[A]-\frac{4}{3}[/tex]
[B]\frac{4}{3}[/tex]
[C]-\frac{3}{4}[/tex]
[D]\frac{3}{4}[/tex]

Answer 1

Step-by-step explanation:

3/(4(x+2)) = x/(x+2)

the common denominator would have to be 4(x+2).

to get the right side to this denominator, we have to multiply numerator and denominator (top and bottom) by 4.

and then we get

3/(4(x+2)) = (4x)/(4(x+2))

and now as both sides are "standing" on the same denominator, we can simply compare only the top parts.

3 = 4x

and therefore we can solve

x = 3/4

and D is then the right answer choice.