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AysviL [449]
2 years ago
5

Factorise the following: c) x - 3x + 2

Mathematics
2 answers:
fenix001 [56]2 years ago
8 0

Answer:

2 ( - x + 2 )

Step-by-step explanation:

x - 3x + 2 = - 2x + 2

- 2x = 2 * - x

2 = 2 * 1

- 2x + 2 = 2 ( - x + 2 )

Hence factorized.

bogdanovich [222]2 years ago
3 0

Answer:

2(−x + 1)

Step-by-step explanation:

x − 3x + 2  = −2x + 2  => 2(−x+1)

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Do the three points lie on one line?
padilas [110]

Answer:

Yes. No graph paper.

Step-by-step explanation:

Let's say the 3 points are A, B, C.

If A, B and C lie on one line then m_{AB} = m_{BC} = m_{AC}

m_{AB} = \frac{y_{B}-y_{A} }{x_{B}-x_{A}} = \frac{2-6}{3-5} = \frac{-4}{-2} = 2\\m_{BC} = \frac{y_{C}-y_{B} }{x_{C}-x_{B}} = \frac{8-2}{6-3} = \frac{6}{3} = 2\\\\m_{AC} = \frac{y_{C}-y_{A} }{x_{C}-x_{A}} = \frac{8-6}{6-5} = \frac{2}{1} = 2\\\\

Hence, they lie on one line.

You don't need to use a graph paper to prove it.

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2 years ago
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3 years ago
Let Ebe the set of all even positive integers in the universe Zof integers, and XE : Z R be the characteristic function of E.
AnnZ [28]

Answer:

\mathbf{X_E (2) =  1}

\mathbf{X_E (-2) = 0 }  

\mathbf{\{ x \in Z: X_E(x) = 1\}  = E}

Step-by-step explanation:

Let E be the set of all even positive integers in the universe Z of integers,

i.e

E = {2,4,6,8,10 ....∞}

X_E : Z \to R be the characteristic function of E.

∴

X_E(x) = \left \{ {{1 \ if  \ x \ \  is \ an \ element \ of \ E} \atop {0 \ if  \ x \ \  is \ not \ an  \ element \ of \ E}} \right.

For XE(2)

\mathbf{X_E (2) =  1}  since x is an element of E (i.e the set of all even numbers)

For XE(-2)

\mathbf{X_E (-2) = 0 }   since  - 2 is less than 0 , and -2 is not an element of E

For { x ∈ Z: XE(x) = 1}

This can be read as:

x which is and element of Z such that X is also an element of x which is equal to 1.

∴

\{ x \in Z: X_E(x) = 1\} = \{ x \in Z | x \in E\} \\ \\  \mathbf{\{ x \in Z: X_E(x) = 1\}  = E}

E = {2,4,6,8,10 ....∞}

5 0
3 years ago
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Answer:

3:4:7

Step-by-step explanation:

14-(3+4)

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red:white:blue

3:4:7

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